Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
To determine which function has a constant additive rate of change of -14, we need to analyze the changes in the [tex]\( y \)[/tex]-values with respect to the changes in the [tex]\( x \)[/tex]-values for the provided data tables. A constant rate of change means that the difference between consecutive [tex]\( y \)[/tex]-values divided by the difference between consecutive [tex]\( x \)[/tex]-values remains the same.
Let's analyze each dataset step-by-step.
Dataset 1:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 20 & -1 \\ \hline 21 & -1.5 \\ \hline 22 & -2 \\ \hline 23 & -2.5 \\ \hline \end{array} \][/tex]
We calculate the rate of change between consecutive points:
1. From [tex]\( x = 20 \)[/tex] to [tex]\( x = 21 \)[/tex]:
[tex]\[ \frac{-1.5 - (-1)}{21 - 20} = \frac{-1.5 + 1}{1} = \frac{-0.5}{1} = -0.5 \][/tex]
2. From [tex]\( x = 21 \)[/tex] to [tex]\( x = 22 \)[/tex]:
[tex]\[ \frac{-2 - (-1.5)}{22 - 21} = \frac{-2 + 1.5}{1} = \frac{-0.5}{1} = -0.5 \][/tex]
3. From [tex]\( x = 22 \)[/tex] to [tex]\( x = 23 \)[/tex]:
[tex]\[ \frac{-2.5 - (-2)}{23 - 22} = \frac{-2.5 + 2}{1} = \frac{-0.5}{1} = -0.5 \][/tex]
The rate of change in Dataset 1 is consistently [tex]\(-0.5\)[/tex]. This is not equal to [tex]\(-14\)[/tex].
Dataset 2:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline -12 & 7 \\ \hline -11 & 11 \\ \hline -10 & 14 \\ \hline -9 & 17 \\ \hline \end{array} \][/tex]
We calculate the rate of change between consecutive points:
1. From [tex]\( x = -12 \)[/tex] to [tex]\( x = -11 \)[/tex]:
[tex]\[ \frac{11 - 7}{-11 - (-12)} = \frac{11 - 7}{-11 + 12} = \frac{4}{1} = 4 \][/tex]
2. From [tex]\( x = -11 \)[/tex] to [tex]\( x = -10 \)[/tex]:
[tex]\[ \frac{14 - 11}{-10 - (-11)} = \frac{14 - 11}{-10 + 11} = \frac{3}{1} = 3 \][/tex]
3. From [tex]\( x = -10 \)[/tex] to [tex]\( x = -9 \)[/tex]:
[tex]\[ \frac{17 - 14}{-9 - (-10)} = \frac{17 - 14}{-9 + 10} = \frac{3}{1} = 3 \][/tex]
The rate of change in Dataset 2 is [tex]\( [4.0, 3.0, 3.0] \)[/tex]. We see that the rate of change is not consistent and certainly not [tex]\(-14\)[/tex].
Conclusion:
Based on the analysis, neither dataset has a constant additive rate of change of [tex]\(-14\)[/tex]. Dataset 1 has a consistent rate of change of [tex]\(-0.5\)[/tex], and Dataset 2 does not have a consistent rate of change at all (4.0, 3.0, 3.0). Therefore, none of the given functions have a constant additive rate of change of [tex]\(-14\)[/tex].
Let's analyze each dataset step-by-step.
Dataset 1:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 20 & -1 \\ \hline 21 & -1.5 \\ \hline 22 & -2 \\ \hline 23 & -2.5 \\ \hline \end{array} \][/tex]
We calculate the rate of change between consecutive points:
1. From [tex]\( x = 20 \)[/tex] to [tex]\( x = 21 \)[/tex]:
[tex]\[ \frac{-1.5 - (-1)}{21 - 20} = \frac{-1.5 + 1}{1} = \frac{-0.5}{1} = -0.5 \][/tex]
2. From [tex]\( x = 21 \)[/tex] to [tex]\( x = 22 \)[/tex]:
[tex]\[ \frac{-2 - (-1.5)}{22 - 21} = \frac{-2 + 1.5}{1} = \frac{-0.5}{1} = -0.5 \][/tex]
3. From [tex]\( x = 22 \)[/tex] to [tex]\( x = 23 \)[/tex]:
[tex]\[ \frac{-2.5 - (-2)}{23 - 22} = \frac{-2.5 + 2}{1} = \frac{-0.5}{1} = -0.5 \][/tex]
The rate of change in Dataset 1 is consistently [tex]\(-0.5\)[/tex]. This is not equal to [tex]\(-14\)[/tex].
Dataset 2:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline -12 & 7 \\ \hline -11 & 11 \\ \hline -10 & 14 \\ \hline -9 & 17 \\ \hline \end{array} \][/tex]
We calculate the rate of change between consecutive points:
1. From [tex]\( x = -12 \)[/tex] to [tex]\( x = -11 \)[/tex]:
[tex]\[ \frac{11 - 7}{-11 - (-12)} = \frac{11 - 7}{-11 + 12} = \frac{4}{1} = 4 \][/tex]
2. From [tex]\( x = -11 \)[/tex] to [tex]\( x = -10 \)[/tex]:
[tex]\[ \frac{14 - 11}{-10 - (-11)} = \frac{14 - 11}{-10 + 11} = \frac{3}{1} = 3 \][/tex]
3. From [tex]\( x = -10 \)[/tex] to [tex]\( x = -9 \)[/tex]:
[tex]\[ \frac{17 - 14}{-9 - (-10)} = \frac{17 - 14}{-9 + 10} = \frac{3}{1} = 3 \][/tex]
The rate of change in Dataset 2 is [tex]\( [4.0, 3.0, 3.0] \)[/tex]. We see that the rate of change is not consistent and certainly not [tex]\(-14\)[/tex].
Conclusion:
Based on the analysis, neither dataset has a constant additive rate of change of [tex]\(-14\)[/tex]. Dataset 1 has a consistent rate of change of [tex]\(-0.5\)[/tex], and Dataset 2 does not have a consistent rate of change at all (4.0, 3.0, 3.0). Therefore, none of the given functions have a constant additive rate of change of [tex]\(-14\)[/tex].
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.