Answered

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Janice measured the mass and the volume of an object. She then determined the density of the object by dividing the object's mass by its volume ([tex]$D=\frac{m}{v}$[/tex]).

Which value would most likely represent the density of the object?

A. [tex]$-1 \, \text{g/cm}^3$[/tex]
B. [tex][tex]$4 \, \text{m/s}$[/tex][/tex]
C. [tex]$-3 \, \text{m/s}$[/tex]
D. [tex]$6 \, \text{g/cm}^3$[/tex]

Sagot :

GinnyAnswer
Let's analyze the given values to determine which one most likely represents the density of the object.

1. [tex]$-1 \, g/cm^3$[/tex]:
- Density is a measure of mass per unit volume, and it cannot be negative. Thus, [tex]$-1 \, g/cm^3$[/tex] does not make physical sense for density.

2. [tex]$4 \, m/s$[/tex]:
- The units here are meters per second (m/s), which is a measure of speed, not density. Therefore, this value does not represent density.

3. [tex]$-3 \, m/s$[/tex]:
- Similar to the previous value, [tex]$-3 \, m/s$[/tex] measures speed with negative value, which is invalid in this context for density. Thus, it doesn't represent density.

4. [tex]$6 \, g/cm^3$[/tex]:
- This value has the appropriate units of grams per cubic centimeter (g/cm^3), which are the correct units for density. Moreover, it is a positive value, consistent with the physical nature of density.

Among all the provided values, the one that most logically and accurately represents the density of the object is:

[tex]\[ 6 \, g/cm^3 \][/tex]
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