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Sagot :
Sure, let's go through the process of naming the organic compounds step-by-step.
### Compound 1: [tex]\( \text{CH}_3 - \text{C} = \text{C} - \text{CH}_3 \)[/tex]
1. Identify the longest carbon chain containing the double bond:
Here, the longest chain contains 4 carbon atoms.
2. Number the chain from the end nearest the double bond:
The double bond is between the second and third carbon.
3. Name the parent hydrocarbon:
Since the chain has 4 carbon atoms, it is a derivative of butene. Since the double bond starts at the second carbon, this is 2-butene.
4. Identify and name the substituents:
There are no substituents in this structure.
Therefore, the name of [tex]\( \text{CH}_3 - \text{C} = \text{C} - \text{CH}_3 \)[/tex] is 2-butene.
### Compound 2: [tex]\( \text{CH}_3 - \text{C} \equiv \text{C} - \text{CH}_3 \)[/tex]
1. Identify the longest carbon chain containing the triple bond:
The longest chain again contains 4 carbon atoms.
2. Number the chain from the end nearest the triple bond:
The triple bond is between the second and third carbon.
3. Name the parent hydrocarbon:
Since the chain has 4 carbon atoms and contains a triple bond starting at the second carbon, it is a derivative of butyne.
Therefore, the name of [tex]\( \text{CH}_3 - \text{C} \equiv \text{C} - \text{CH}_3 \)[/tex] is 2-butyne.
So, the names of the compounds are:
1. 2-butene
2. 2-butyne
### Compound 1: [tex]\( \text{CH}_3 - \text{C} = \text{C} - \text{CH}_3 \)[/tex]
1. Identify the longest carbon chain containing the double bond:
Here, the longest chain contains 4 carbon atoms.
2. Number the chain from the end nearest the double bond:
The double bond is between the second and third carbon.
3. Name the parent hydrocarbon:
Since the chain has 4 carbon atoms, it is a derivative of butene. Since the double bond starts at the second carbon, this is 2-butene.
4. Identify and name the substituents:
There are no substituents in this structure.
Therefore, the name of [tex]\( \text{CH}_3 - \text{C} = \text{C} - \text{CH}_3 \)[/tex] is 2-butene.
### Compound 2: [tex]\( \text{CH}_3 - \text{C} \equiv \text{C} - \text{CH}_3 \)[/tex]
1. Identify the longest carbon chain containing the triple bond:
The longest chain again contains 4 carbon atoms.
2. Number the chain from the end nearest the triple bond:
The triple bond is between the second and third carbon.
3. Name the parent hydrocarbon:
Since the chain has 4 carbon atoms and contains a triple bond starting at the second carbon, it is a derivative of butyne.
Therefore, the name of [tex]\( \text{CH}_3 - \text{C} \equiv \text{C} - \text{CH}_3 \)[/tex] is 2-butyne.
So, the names of the compounds are:
1. 2-butene
2. 2-butyne
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