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Two points located on [tex] \overleftrightarrow{ JK } [/tex] are [tex] J(1,-4) [/tex] and [tex] K(-2,8) [/tex]. What is the slope of [tex] \overleftrightarrow{ JK } [/tex]?

A. -4
B. -2
C. [tex] -\frac{1}{4} [/tex]
D. [tex] \frac{1}{4} [/tex]
E. 4

Sagot :

GinnyAnswer
To find the slope of the line passing through the points \( J(1, -4) \) and \( K(-2, 8) \), we will use the slope formula:

[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]

Here, the points \( J \) and \( K \) are given as \( J(x_1, y_1) = (1, -4) \) and \( K(x_2, y_2) = (-2, 8) \).

Let's substitute the coordinates into the slope formula:

[tex]\[ m = \frac{8 - (-4)}{-2 - 1} \][/tex]

Calculate the differences in the numerator and the denominator:

[tex]\[ m = \frac{8 + 4}{-2 - 1} \][/tex]

[tex]\[ m = \frac{12}{-3} \][/tex]

Simplify the fraction:

[tex]\[ m = -4 \][/tex]

So, the slope of the line passing through the points \( J(1, -4) \) and \( K(-2, 8) \) is \(-4\).

Therefore, the correct answer is:

A. [tex]\(-4\)[/tex]
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