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Solve the system of equations using substitution.

[tex]\[
\begin{array}{l}
y = 4x \\
y = 8x + 8
\end{array}
\][/tex]

Choose the correct solution:
A. \((-3, -12)\)
B. \((-2, -8)\)
C. \((2, 8)\)
D. [tex]\((3, 12)\)[/tex]


Sagot :

Certainly! To solve the system of linear equations using the substitution method, we have the following equations:

[tex]\[ \begin{array}{l} y = 4x \\ y = 8x + 8 \end{array} \][/tex]

1. Step 1: Substitute the value of \( y \) from the first equation into the second equation.

Given \( y = 4x \), we can replace \( y \) in the second equation \( y = 8x + 8 \).

So, substituting \( y \) in the second equation, we get:
[tex]\[ 4x = 8x + 8 \][/tex]

2. Step 2: Solve for \( x \).

Rearrange the equation to move all terms involving \( x \) to one side:
[tex]\[ 4x - 8x = 8 \][/tex]

Simplify the left-hand side:
[tex]\[ -4x = 8 \][/tex]

Divide both sides by \(-4\) to solve for \( x \):
[tex]\[ x = -2 \][/tex]

3. Step 3: Substitute \( x \) back into the first equation to find \( y \).

Now, substitute \( x = -2 \) back into the first equation \( y = 4x \):
[tex]\[ y = 4(-2) \][/tex]

Simplify to find \( y \):
[tex]\[ y = -8 \][/tex]

So, the solution to the system of equations is:
[tex]\[ (x, y) = (-2, -8) \][/tex]

To confirm, the correct solution from the given options is:
[tex]\[ (-2, -8) \][/tex]
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