Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Find the inverse of the function [tex] y = 2x^2 + 2 [/tex]

A. [tex] y = \pm \sqrt{x-2} [/tex]
B. [tex] y = \pm \sqrt{\frac{1}{2} x - 1} [/tex]
C. [tex] y = \pm \sqrt{2x^2 - 4} [/tex]
D. [tex] y = \pm \sqrt{\frac{1}{2} x - 1} [/tex]


Sagot :

Certainly! Let me guide you through the process of finding the inverse of the function \( y = 2x^2 + 2 \) step-by-step.

### Step-by-Step Solution:

1. Express the function: Start by writing down the original function:
[tex]\[ y = 2x^2 + 2 \][/tex]

2. Solve for \( x \) in terms of \( y \): To find the inverse, we need to solve this equation for \( x \):

a. Subtract 2 from both sides to isolate the quadratic term:
[tex]\[ y - 2 = 2x^2 \][/tex]

b. Divide both sides by 2:
[tex]\[ \frac{y - 2}{2} = x^2 \][/tex]

c. Take the square root of both sides. Because squaring can yield both a positive and a negative result, we get two solutions:
[tex]\[ x = \pm \sqrt{\frac{y - 2}{2}} \][/tex]

3. Express the inverse function: Now we have solved for \( x \) in terms of \( y \), representing the inverse function. To write it in the conventional \( y \)-form, we swap \( x \) and \( y \):

[tex]\[ y = \pm \sqrt{\frac{x - 2}{2}} \][/tex]

### Conclusion:

The inverse of the function \( y = 2x^2 + 2 \) is:

[tex]\[ y = \pm \sqrt{\frac{x - 2}{2}} \][/tex]

This means for every [tex]\( x \)[/tex] in the domain of the inverse function, there can be two possible [tex]\( y \)[/tex] values, one positive and one negative, corresponding to the square roots.