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Sagot :
To determine how many moles of \( CO_2 \) are present in 454 grams of the substance, we can follow these steps:
1. Identify the Given Data:
- Mass of \( CO_2 \) provided = 454 grams.
2. Determine the Molar Mass of \( CO_2 \):
- The formula for carbon dioxide (\( CO_2 \)) consists of one carbon (C) atom and two oxygen (O) atoms.
- Atomic mass of carbon (C) = 12 grams per mole.
- Atomic mass of oxygen (O) = 16 grams per mole.
- Therefore, the molar mass of \( CO_2 \) is calculated as:
[tex]\[ \text{Molar mass of } CO_2 = 12 + (2 \times 16) = 12 + 32 = 44 \text{ grams per mole}. \][/tex]
3. Calculate the Number of Moles:
- The number of moles of a substance is calculated by dividing the mass of the substance by its molar mass.
- Using this relationship, we have:
[tex]\[ \text{Number of Moles} = \frac{\text{Mass of } CO_2}{\text{Molar Mass of } CO_2} \][/tex]
- Substituting the values given:
[tex]\[ \text{Number of Moles} = \frac{454 \text{ grams}}{44 \text{ grams per mole}} \approx 10.318181818181818 \text{ moles} \][/tex]
Hence, the number of moles present in 454 grams of \( CO_2 \) is approximately 10.31 moles.
Therefore, the correct answer is:
A. [tex]\( \quad 10.31 \text{ mol} \)[/tex]
1. Identify the Given Data:
- Mass of \( CO_2 \) provided = 454 grams.
2. Determine the Molar Mass of \( CO_2 \):
- The formula for carbon dioxide (\( CO_2 \)) consists of one carbon (C) atom and two oxygen (O) atoms.
- Atomic mass of carbon (C) = 12 grams per mole.
- Atomic mass of oxygen (O) = 16 grams per mole.
- Therefore, the molar mass of \( CO_2 \) is calculated as:
[tex]\[ \text{Molar mass of } CO_2 = 12 + (2 \times 16) = 12 + 32 = 44 \text{ grams per mole}. \][/tex]
3. Calculate the Number of Moles:
- The number of moles of a substance is calculated by dividing the mass of the substance by its molar mass.
- Using this relationship, we have:
[tex]\[ \text{Number of Moles} = \frac{\text{Mass of } CO_2}{\text{Molar Mass of } CO_2} \][/tex]
- Substituting the values given:
[tex]\[ \text{Number of Moles} = \frac{454 \text{ grams}}{44 \text{ grams per mole}} \approx 10.318181818181818 \text{ moles} \][/tex]
Hence, the number of moles present in 454 grams of \( CO_2 \) is approximately 10.31 moles.
Therefore, the correct answer is:
A. [tex]\( \quad 10.31 \text{ mol} \)[/tex]
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