To determine the probability that the third digit in a locker combination consisting of three unique nonzero digits (1 through 9) is even, given that the first two digits are even, let's break down the problem step-by-step:
1. Identify nonzero digits and even digits:
- There are a total of 9 nonzero digits: {1, 2, 3, 4, 5, 6, 7, 8, 9}.
- Among these, the even digits are 2, 4, 6, and 8. There are 4 even digits in total.
2. Determine the total number of digits after selecting the first two even digits:
- Since the first two digits are even, we select 2 digits from the 4 available even digits.
- After selecting the first two even digits, there are 7 digits remaining (9 total digits - 2 selected digits).
3. Determine the number of remaining even digits:
- We initially had 4 even digits, and we’ve already used 2 of them for the first two positions.
- Therefore, there are 2 remaining even digits.
4. Calculate the probability that the third digit is even:
- The total number of remaining digits is 7.
- The remaining even digits among these 7 are 2.
The probability that the third digit is even is given by the ratio of the number of remaining even digits to the total number of remaining digits:
[tex]\[
\text{Probability} = \frac{\text{Number of remaining even digits}}{\text{Total number of remaining digits}} = \frac{2}{7}
\][/tex]
Therefore, the correct answer is:
[tex]\[
\boxed{\frac{2}{7}}
\][/tex]
