Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
To determine the relationship between the given x and y values and to predict the missing y value for \(x = 5\), we start by assuming that y follows a linear relationship with x. This can be represented by the equation of a line:
[tex]\[ y = mx + c \][/tex]
where \(m\) is the slope of the line and \(c\) is the y-intercept.
### Step-by-Step Solution:
1. Identify the given values:
We have the following data points:
[tex]\[ \begin{array}{|c|c|c|c|c|c|} \hline x & 1 & 2 & 3 & 4 & 5 \\ \hline y & 13 & 21 & 29 & 37 & ? \\ \hline \end{array} \][/tex]
2. Formulate the system of equations:
From the given points (1, 13), (2, 21), (3, 29), and (4, 37), we set up the following system of equations based on the line equation \( y = mx + c \):
[tex]\[ \begin{cases} 13 = m \cdot 1 + c \\ 21 = m \cdot 2 + c \\ 29 = m \cdot 3 + c \\ 37 = m \cdot 4 + c \end{cases} \][/tex]
3. Find the slope (m) and y-intercept (c):
By solving these equations, we get the following results for the coefficients:
[tex]\[ m = 8, \quad c = 5 \][/tex]
Substituting these values back into the line equation, we get:
[tex]\[ y = 8x + 5 \][/tex]
4. Predict the missing y value for \(x = 5\):
We now use the derived equation of the line to predict the y value when \(x = 5\):
[tex]\[ y = 8 \cdot 5 + 5 \][/tex]
[tex]\[ y = 40 + 5 \][/tex]
[tex]\[ y = 45 \][/tex]
### Final Answer:
The coefficients of the line are:
[tex]\[ m = 8, \quad c = 5 \][/tex]
The predicted y value for \(x = 5\) is:
[tex]\[ y = 45 \][/tex]
Thus, the completed table is:
[tex]\[ \begin{array}{|c|c|c|c|c|c|} \hline x & 1 & 2 & 3 & 4 & 5 \\ \hline y & 13 & 21 & 29 & 37 & 45 \\ \hline \end{array} \][/tex]
[tex]\[ y = mx + c \][/tex]
where \(m\) is the slope of the line and \(c\) is the y-intercept.
### Step-by-Step Solution:
1. Identify the given values:
We have the following data points:
[tex]\[ \begin{array}{|c|c|c|c|c|c|} \hline x & 1 & 2 & 3 & 4 & 5 \\ \hline y & 13 & 21 & 29 & 37 & ? \\ \hline \end{array} \][/tex]
2. Formulate the system of equations:
From the given points (1, 13), (2, 21), (3, 29), and (4, 37), we set up the following system of equations based on the line equation \( y = mx + c \):
[tex]\[ \begin{cases} 13 = m \cdot 1 + c \\ 21 = m \cdot 2 + c \\ 29 = m \cdot 3 + c \\ 37 = m \cdot 4 + c \end{cases} \][/tex]
3. Find the slope (m) and y-intercept (c):
By solving these equations, we get the following results for the coefficients:
[tex]\[ m = 8, \quad c = 5 \][/tex]
Substituting these values back into the line equation, we get:
[tex]\[ y = 8x + 5 \][/tex]
4. Predict the missing y value for \(x = 5\):
We now use the derived equation of the line to predict the y value when \(x = 5\):
[tex]\[ y = 8 \cdot 5 + 5 \][/tex]
[tex]\[ y = 40 + 5 \][/tex]
[tex]\[ y = 45 \][/tex]
### Final Answer:
The coefficients of the line are:
[tex]\[ m = 8, \quad c = 5 \][/tex]
The predicted y value for \(x = 5\) is:
[tex]\[ y = 45 \][/tex]
Thus, the completed table is:
[tex]\[ \begin{array}{|c|c|c|c|c|c|} \hline x & 1 & 2 & 3 & 4 & 5 \\ \hline y & 13 & 21 & 29 & 37 & 45 \\ \hline \end{array} \][/tex]
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.