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A pea plant with genotype PP (purple flowers) mates with a plant with the genotype pp (white flowers). The dominant allele P codes for purple flowers. The possibility that the offspring will have purple flowers is [tex]$\square$[/tex]. If an offspring from this cross mates with a pp plant, the possibility of a homozygous dominant genotype for the flowers will be [tex]$\square$[/tex].

[tex]\[
\begin{tabular}{|c|c|c|}
\hline
& P & P \\
\hline
p & Pp & Pp \\
\hline
p & Pp & Pp \\
\hline
\end{tabular}
\][/tex]

[tex]\[
\begin{tabular}{|c|c|c|}
\hline
& P & p \\
\hline
p & Pp & pp \\
\hline
p & Pp & pp \\
\hline
\end{tabular}
\][/tex]

Sagot :

GinnyAnswer
Let's analyze the problem step-by-step:

1. Initial Cross: PP x pp
- Genotype of Parent 1: PP (homozygous dominant, purple flowers)
- Genotype of Parent 2: pp (homozygous recessive, white flowers)

When we cross PP with pp, all offspring will inherit one allele from each parent:
- Parent 1 (PP) can only contribute a P allele.
- Parent 2 (pp) can only contribute a p allele.

So, all offspring will have the genotype Pp (heterozygous):
- Pp

Since the P allele is dominant, these offspring will all have purple flowers.

Therefore, the probability that the offspring from this cross will have purple flowers is:
- [tex]\( 1.0 \)[/tex]

2. Second Cross: Pp x pp
- One offspring from the first cross has the genotype Pp (heterozygous, purple flowers).
- Cross this offspring with a plant that is pp (homozygous recessive, white flowers).

Constructing a Punnett square for Pp x pp:
```
| | p | p |
|---|---|---|
| P | Pp| Pp|
| p | pp| pp|
```

The possible genotypes for the next generation (second cross) are:
- Pp (heterozygous, purple flowers)
- pp (homozygous recessive, white flowers)

Counting occurrences:
- Pp: 2 (purple flowers)
- pp: 2 (white flowers)

Therefore, there are no PP genotypes in the second cross.

The probability of having a homozygous dominant genotype (PP) in this cross is:
- [tex]\( 0.0 \)[/tex]

In summary:
- The probability that the offspring from the first cross (PP x pp) will have purple flowers is [tex]\( 1.0 \)[/tex].
- The probability of an offspring from the second cross (Pp x pp) being homozygous dominant for purple flowers (PP) is [tex]\( 0.0 \)[/tex].

Let's fill in the drop-down menus:

1. The probability that the offspring will have purple flowers is [tex]\( \boxed{1.0} \)[/tex].
2. The probability of homozygous dominant genotype for the flowers will be [tex]\( \boxed{0.0} \)[/tex].
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