At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Let's balance each of these chemical equations step-by-step.
### Equation 1: [tex]\( CH_4 + O_2 \rightarrow CO_2 + H_2O \)[/tex]
1. Identify the atoms present on each side:
- Reactants: 1 C, 4 H, 2 O
- Products: 1 C, 2 H, 3 O
2. Balance Carbon (C):
- There is 1 carbon atom on each side already, so carbon is balanced.
3. Balance Hydrogen (H):
- There are 4 hydrogen atoms on the reactant side (from [tex]\(CH_4\)[/tex]) and 2 hydrogen atoms on the product side (from [tex]\(H_2O\)[/tex]).
- To balance hydrogen, place a coefficient of 2 in front of [tex]\(H_2O\)[/tex]:
[tex]\[ CH_4 + O_2 \rightarrow CO_2 + 2H_2O \][/tex]
- Now, the hydrogen atoms are balanced (4 H atoms on each side).
4. Balance Oxygen (O):
- There are now 2 oxygen atoms from [tex]\(CO_2\)[/tex] and [tex]\(2\times1=2\)[/tex] oxygen atoms from [tex]\(2H_2O\)[/tex], resulting in a total of 4 oxygen atoms on the product side.
- On the reactant side, we currently only have [tex]\(O_2\)[/tex], which gives 2 oxygen atoms.
- To balance the oxygen atoms, place a coefficient of 2 in front of [tex]\(O_2\)[/tex]:
[tex]\[ CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O \][/tex]
- Now, the oxygen atoms are balanced (4 O atoms on each side).
The balanced equation is:
[tex]\[ CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O \][/tex]
### Equation 2: [tex]\( CaCl_2 + \square AgNO_3 \rightarrow Ca\left(NO_3\right)_2 + \square AgCl \)[/tex]
1. Identify the atoms present on each side:
- Reactants: 1 Ca, 2 Cl, 1 Ag, 1 N, 3 O
- Products: 1 Ca, 2 NO_3, 2 Ag, 2 Cl
2. Balance Calcium (Ca):
- There's 1 Ca atom on each side, so calcium is balanced.
3. Balance Chlorine (Cl):
- There's 2 Cl atoms on the reactant side (from [tex]\(CaCl_2\)[/tex]) and 1 Cl atom on the product side (from [tex]\(AgCl\)[/tex]).
- To balance chlorine, place a coefficient of 2 in front of [tex]\(AgCl\)[/tex]:
[tex]\[ CaCl_2 + AgNO_3 \rightarrow Ca\left(NO_3\right)_2 + 2AgCl \][/tex]
- Now, the chlorine atoms are balanced (2 Cl atoms on each side).
4. Balance Silver (Ag):
- Now, there are 2 Ag atoms needed on the reactant side.
- Place a coefficient of 2 in front of [tex]\(AgNO_3\)[/tex]:
[tex]\[ CaCl_2 + 2AgNO_3 \rightarrow Ca\left(NO_3\right)_2 + 2AgCl \][/tex]
- Now, the silver atoms are balanced (2 Ag atoms on each side).
5. Verify Nitrogen (N) and Oxygen (O):
- Nitrogen: 2 NO_3 groups on the product side corresponds to 2 N atoms (and 6 O atoms).
- Reactants now have [tex]\( 2\times1=2\)[/tex] N atoms and [tex]\(2\times3=6\)[/tex] O atoms from [tex]\(2AgNO_3\)[/tex], which is balanced with the product side.
The balanced equation is:
[tex]\[ CaCl_2 + 2AgNO_3 \rightarrow Ca\left(NO_3\right)_2 + 2AgCl \][/tex]
### Equation 3: [tex]\( C_2H_6O + O_2 \rightarrow CO_2 + H_2O \)[/tex]
1. Identify the atoms present on each side:
- Reactants: 2 C, 6 H, x O
- Products: y C, z H, w O
2. Balance Carbon (C):
- There are 2 carbon atoms in [tex]\(C_2H_6O\)[/tex].
- Place a coefficient of 2 in front of [tex]\(CO_2\)[/tex]:
[tex]\[ C_2H_6O + O_2 \rightarrow 2CO_2 + H_2O \][/tex]
- Now, the carbon atoms are balanced (2 C atoms on each side).
3. Balance Hydrogen (H):
- There are 6 hydrogen atoms in [tex]\(C_2H_6O\)[/tex] and 2 hydrogen atoms in [tex]\(H_2O\)[/tex].
- Place a coefficient of 3 in front of [tex]\(H_2O\)[/tex]:
[tex]\[ C_2H_6O + O_2 \rightarrow 2CO_2 + 3H_2O \][/tex]
- Now, the hydrogen atoms are balanced (6 H atoms on each side).
4. Balance Oxygen (O):
- There are [tex]\(2\times2=4\)[/tex] oxygen atoms from [tex]\(CO_2\)[/tex] and [tex]\(3 \times 1 = 3\)[/tex] oxygen atoms from [tex]\(H_2O\)[/tex], resulting in a total of 7 oxygen atoms on the product side.
- On the reactant side, we have 1 oxygen in [tex]\(C_2H_6O\)[/tex] and the rest must come from [tex]\(O_2\)[/tex].
- To get 7 oxygen atoms in total, [tex]\(1 + 2 \times \left( x \right) = 7 \Rightarrow x = 3\)[/tex]:
[tex]\[ C_2H_6O + 3O_2 \rightarrow 2CO_2 + 3H_2O \][/tex]
The balanced equation is:
[tex]\[ C_2H_6O + 3O_2 \rightarrow 2CO_2 + 3H_2O \][/tex]
So, the final balanced equations are:
[tex]\[ CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O \][/tex]
[tex]\[ CaCl_2 + 2AgNO_3 \rightarrow Ca\left(NO_3\right)_2 + 2AgCl \][/tex]
[tex]\[ C_2H_6O + 3O_2 \rightarrow 2CO_2 + 3H_2O \][/tex]
### Equation 1: [tex]\( CH_4 + O_2 \rightarrow CO_2 + H_2O \)[/tex]
1. Identify the atoms present on each side:
- Reactants: 1 C, 4 H, 2 O
- Products: 1 C, 2 H, 3 O
2. Balance Carbon (C):
- There is 1 carbon atom on each side already, so carbon is balanced.
3. Balance Hydrogen (H):
- There are 4 hydrogen atoms on the reactant side (from [tex]\(CH_4\)[/tex]) and 2 hydrogen atoms on the product side (from [tex]\(H_2O\)[/tex]).
- To balance hydrogen, place a coefficient of 2 in front of [tex]\(H_2O\)[/tex]:
[tex]\[ CH_4 + O_2 \rightarrow CO_2 + 2H_2O \][/tex]
- Now, the hydrogen atoms are balanced (4 H atoms on each side).
4. Balance Oxygen (O):
- There are now 2 oxygen atoms from [tex]\(CO_2\)[/tex] and [tex]\(2\times1=2\)[/tex] oxygen atoms from [tex]\(2H_2O\)[/tex], resulting in a total of 4 oxygen atoms on the product side.
- On the reactant side, we currently only have [tex]\(O_2\)[/tex], which gives 2 oxygen atoms.
- To balance the oxygen atoms, place a coefficient of 2 in front of [tex]\(O_2\)[/tex]:
[tex]\[ CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O \][/tex]
- Now, the oxygen atoms are balanced (4 O atoms on each side).
The balanced equation is:
[tex]\[ CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O \][/tex]
### Equation 2: [tex]\( CaCl_2 + \square AgNO_3 \rightarrow Ca\left(NO_3\right)_2 + \square AgCl \)[/tex]
1. Identify the atoms present on each side:
- Reactants: 1 Ca, 2 Cl, 1 Ag, 1 N, 3 O
- Products: 1 Ca, 2 NO_3, 2 Ag, 2 Cl
2. Balance Calcium (Ca):
- There's 1 Ca atom on each side, so calcium is balanced.
3. Balance Chlorine (Cl):
- There's 2 Cl atoms on the reactant side (from [tex]\(CaCl_2\)[/tex]) and 1 Cl atom on the product side (from [tex]\(AgCl\)[/tex]).
- To balance chlorine, place a coefficient of 2 in front of [tex]\(AgCl\)[/tex]:
[tex]\[ CaCl_2 + AgNO_3 \rightarrow Ca\left(NO_3\right)_2 + 2AgCl \][/tex]
- Now, the chlorine atoms are balanced (2 Cl atoms on each side).
4. Balance Silver (Ag):
- Now, there are 2 Ag atoms needed on the reactant side.
- Place a coefficient of 2 in front of [tex]\(AgNO_3\)[/tex]:
[tex]\[ CaCl_2 + 2AgNO_3 \rightarrow Ca\left(NO_3\right)_2 + 2AgCl \][/tex]
- Now, the silver atoms are balanced (2 Ag atoms on each side).
5. Verify Nitrogen (N) and Oxygen (O):
- Nitrogen: 2 NO_3 groups on the product side corresponds to 2 N atoms (and 6 O atoms).
- Reactants now have [tex]\( 2\times1=2\)[/tex] N atoms and [tex]\(2\times3=6\)[/tex] O atoms from [tex]\(2AgNO_3\)[/tex], which is balanced with the product side.
The balanced equation is:
[tex]\[ CaCl_2 + 2AgNO_3 \rightarrow Ca\left(NO_3\right)_2 + 2AgCl \][/tex]
### Equation 3: [tex]\( C_2H_6O + O_2 \rightarrow CO_2 + H_2O \)[/tex]
1. Identify the atoms present on each side:
- Reactants: 2 C, 6 H, x O
- Products: y C, z H, w O
2. Balance Carbon (C):
- There are 2 carbon atoms in [tex]\(C_2H_6O\)[/tex].
- Place a coefficient of 2 in front of [tex]\(CO_2\)[/tex]:
[tex]\[ C_2H_6O + O_2 \rightarrow 2CO_2 + H_2O \][/tex]
- Now, the carbon atoms are balanced (2 C atoms on each side).
3. Balance Hydrogen (H):
- There are 6 hydrogen atoms in [tex]\(C_2H_6O\)[/tex] and 2 hydrogen atoms in [tex]\(H_2O\)[/tex].
- Place a coefficient of 3 in front of [tex]\(H_2O\)[/tex]:
[tex]\[ C_2H_6O + O_2 \rightarrow 2CO_2 + 3H_2O \][/tex]
- Now, the hydrogen atoms are balanced (6 H atoms on each side).
4. Balance Oxygen (O):
- There are [tex]\(2\times2=4\)[/tex] oxygen atoms from [tex]\(CO_2\)[/tex] and [tex]\(3 \times 1 = 3\)[/tex] oxygen atoms from [tex]\(H_2O\)[/tex], resulting in a total of 7 oxygen atoms on the product side.
- On the reactant side, we have 1 oxygen in [tex]\(C_2H_6O\)[/tex] and the rest must come from [tex]\(O_2\)[/tex].
- To get 7 oxygen atoms in total, [tex]\(1 + 2 \times \left( x \right) = 7 \Rightarrow x = 3\)[/tex]:
[tex]\[ C_2H_6O + 3O_2 \rightarrow 2CO_2 + 3H_2O \][/tex]
The balanced equation is:
[tex]\[ C_2H_6O + 3O_2 \rightarrow 2CO_2 + 3H_2O \][/tex]
So, the final balanced equations are:
[tex]\[ CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O \][/tex]
[tex]\[ CaCl_2 + 2AgNO_3 \rightarrow Ca\left(NO_3\right)_2 + 2AgCl \][/tex]
[tex]\[ C_2H_6O + 3O_2 \rightarrow 2CO_2 + 3H_2O \][/tex]
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
