Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
To solve the equation [tex]\(\frac{p+1}{3} = \frac{p+1}{4}\)[/tex], we need to find the value of [tex]\(p\)[/tex] that satisfies this equality. Let's go through this step-by-step.
1. Write down the equation:
[tex]\[ \frac{p+1}{3} = \frac{p+1}{4} \][/tex]
2. Eliminate the fractions by finding a common denominator, which in this case is 12. Multiply every term by 12:
[tex]\[ 12 \cdot \frac{p+1}{3} = 12 \cdot \frac{p+1}{4} \][/tex]
3. Simplify both sides:
[tex]\[ 4(p+1) = 3(p+1) \][/tex]
4. Distribute the constants on both sides:
[tex]\[ 4p + 4 = 3p + 3 \][/tex]
5. Bring all terms involving [tex]\(p\)[/tex] to one side and constants to the opposite side. Subtract [tex]\(3p\)[/tex] and [tex]\(3\)[/tex] from both sides:
[tex]\[ 4p + 4 - 3p - 3 = 0 \][/tex]
[tex]\[ p + 1 = 0 \][/tex]
6. Solve for [tex]\(p\)[/tex]:
[tex]\[ p = -1 \][/tex]
7. Verify the solution: To ensure [tex]\(p = -1\)[/tex] is correct, substitute [tex]\(p = -1\)[/tex] back into the original equation:
[tex]\[ \frac{(-1)+1}{3} = \frac{(-1)+1}{4} \][/tex]
[tex]\[ \frac{0}{3} = \frac{0}{4} \][/tex]
[tex]\[ 0 = 0 \][/tex]
Since both sides of the equation are equal when [tex]\(p = -1\)[/tex], this value satisfies the equation.
Therefore, the value of [tex]\(p\)[/tex] that makes the equation true is:
[tex]\[ \boxed{-1} \][/tex]
1. Write down the equation:
[tex]\[ \frac{p+1}{3} = \frac{p+1}{4} \][/tex]
2. Eliminate the fractions by finding a common denominator, which in this case is 12. Multiply every term by 12:
[tex]\[ 12 \cdot \frac{p+1}{3} = 12 \cdot \frac{p+1}{4} \][/tex]
3. Simplify both sides:
[tex]\[ 4(p+1) = 3(p+1) \][/tex]
4. Distribute the constants on both sides:
[tex]\[ 4p + 4 = 3p + 3 \][/tex]
5. Bring all terms involving [tex]\(p\)[/tex] to one side and constants to the opposite side. Subtract [tex]\(3p\)[/tex] and [tex]\(3\)[/tex] from both sides:
[tex]\[ 4p + 4 - 3p - 3 = 0 \][/tex]
[tex]\[ p + 1 = 0 \][/tex]
6. Solve for [tex]\(p\)[/tex]:
[tex]\[ p = -1 \][/tex]
7. Verify the solution: To ensure [tex]\(p = -1\)[/tex] is correct, substitute [tex]\(p = -1\)[/tex] back into the original equation:
[tex]\[ \frac{(-1)+1}{3} = \frac{(-1)+1}{4} \][/tex]
[tex]\[ \frac{0}{3} = \frac{0}{4} \][/tex]
[tex]\[ 0 = 0 \][/tex]
Since both sides of the equation are equal when [tex]\(p = -1\)[/tex], this value satisfies the equation.
Therefore, the value of [tex]\(p\)[/tex] that makes the equation true is:
[tex]\[ \boxed{-1} \][/tex]
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.