To determine how many grams of aluminum are required to produce 8.00 moles of aluminum chloride (AlCl₃), we can follow these steps:
1. Determine the molar relationship from the balanced chemical equation:
The balanced chemical equation given is:
[tex]\[
2 \text{Al} + 3 \text{Cl}_2 \rightarrow 2 \text{AlCl}_3
\][/tex]
From the equation, we see that 2 moles of aluminum (Al) produce 2 moles of aluminum chloride (AlCl₃).
2. Identify the molar relationship:
The stoichiometry tells us that 1 mole of aluminum (Al) produces 1 mole of aluminum chloride (AlCl₃).
3. Calculate the moles of aluminum needed:
Given that we need to produce 8.00 moles of aluminum chloride (AlCl₃), the moles of aluminum required are equal to the moles of AlCl₃ produced. Therefore, we need 8.00 moles of aluminum (Al).
4. Use the molar mass of aluminum to find the required grams:
The molar mass of aluminum (Al) is given as 26.98 g/mol.
5. Calculate the mass of aluminum:
To convert moles of aluminum to grams, use the formula:
[tex]\[
\text{mass} = \text{moles} \times \text{molar mass}
\][/tex]
Substituting in the values:
[tex]\[
\text{mass of Al} = 8.00 \text{ moles} \times 26.98 \text{ g/mol} = 215.84 \text{ grams}
\][/tex]
Thus, to produce 8.00 moles of aluminum chloride (AlCl₃), you need 215.84 grams of aluminum (Al).
