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A current of [tex]0.050 \text{ amps}[/tex] flows in a circuit element with a resistance of 100 ohms. What is the voltage drop across the circuit element? (Use Ohm's law: [tex]V = IR[/tex])

A. [tex]5.0 \text{ V}[/tex]
B. [tex]50 \text{ V}[/tex]
C. [tex]500 \text{ V}[/tex]
D. [tex]0.50 \text{ V}[/tex]

Sagot :

GinnyAnswer
To find the voltage drop across a circuit element, we use Ohm's Law, which states that the voltage ([tex]\(V\)[/tex]) across a resistor is equal to the current ([tex]\(I\)[/tex]) flowing through it multiplied by the resistance ([tex]\(R\)[/tex]) of the resistor. The formula is given as:

[tex]\[ V = I \times R \][/tex]

Here, we are provided with:
- The current, [tex]\(I = 0.050 \text{ amps} \)[/tex]
- The resistance, [tex]\(R = 100 \text{ ohms} \)[/tex]

Following the steps:

1. Write down the formula:
[tex]\[ V = I \times R \][/tex]

2. Substitute the given values:
[tex]\[ V = 0.050 \text{ amps} \times 100 \text{ ohms} \][/tex]

3. Perform the multiplication:
[tex]\[ V = 0.050 \times 100 = 5.0 \text{ volts} \][/tex]

Thus, the voltage drop across the circuit element is found to be:

[tex]\[ V = 5.0 \text{ volts} \][/tex]

Therefore, the correct answer is:

A. [tex]\( 5.0 \text{ V} \)[/tex]
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