Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

If [tex][tex]$h(x)=(f \circ g)(x)$[/tex][/tex] and [tex][tex]$h(x)=\sqrt{x+5}$[/tex][/tex], find [tex][tex]$g(x)$[/tex][/tex] if [tex][tex]$f(x)=\sqrt{x+2}$[/tex][/tex].

Sagot :

To solve for [tex]\( g(x) \)[/tex] given the functions [tex]\( h(x) \)[/tex] and [tex]\( f(x) \)[/tex], we need to understand the relationship between these functions. The composition [tex]\( (f \circ g)(x) \)[/tex] means that we apply [tex]\( g(x) \)[/tex] first and then apply [tex]\( f \)[/tex].

Given the following:
[tex]\[ h(x) = \sqrt{x + 5} \][/tex]
[tex]\[ f(x) = \sqrt{x + 2} \][/tex]
and the relationship:
[tex]\[ h(x) = (f \circ g)(x) \][/tex]

This implies that:
[tex]\[ h(x) = f(g(x)) \][/tex]

We can set the function definitions equal:
[tex]\[ \sqrt{x + 5} = \sqrt{g(x) + 2} \][/tex]

To simplify this equation, we can eliminate the square roots by squaring both sides:
[tex]\[ (\sqrt{x + 5})^2 = (\sqrt{g(x) + 2})^2 \][/tex]

This simplifies to:
[tex]\[ x + 5 = g(x) + 2 \][/tex]

Now, solve for [tex]\( g(x) \)[/tex]:
[tex]\[ x + 5 = g(x) + 2 \implies g(x) = x + 5 - 2 \implies g(x) = x + 3 \][/tex]

Therefore, the function [tex]\( g(x) \)[/tex] is:
[tex]\[ g(x) = x + 3 \][/tex]
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.