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Solve the inequality for [tex]b[/tex].

[tex]10 \leq -\frac{2}{3}(9 + 12b)[/tex]

A. [tex]b \leq -2[/tex]
B. [tex]b \geq -2[/tex]
C. [tex]b \leq \frac{4}{3}[/tex]
D. [tex]b \geq \frac{4}{3}[/tex]

Sagot :

GinnyAnswer
Let's solve the inequality step-by-step to find the value of [tex]\( b \)[/tex]:

The given inequality is:
[tex]\[ 10 \leq -\frac{2}{3}(9 + 12b) \][/tex]

Step 1: Distribute and simplify the expression inside the parentheses.
[tex]\[ -\frac{2}{3}(9 + 12b) = -\frac{2}{3} \cdot 9 + -\frac{2}{3} \cdot 12b \][/tex]
[tex]\[ = -6 - 8b \][/tex]

Thus, the inequality becomes:
[tex]\[ 10 \leq -6 - 8b \][/tex]

Step 2: Add 6 to both sides of the inequality to isolate the term with [tex]\( b \)[/tex]:
[tex]\[ 10 + 6 \leq -8b \][/tex]
[tex]\[ 16 \leq -8b \][/tex]

Step 3: Divide both sides by -8. Since we are dividing by a negative number, remember to reverse the inequality sign:
[tex]\[ \frac{16}{-8} \geq b \][/tex]
[tex]\[ -2 \geq b \][/tex]

Rewriting this, we get:
[tex]\[ b \leq -2 \][/tex]

So, the solution to the inequality is:
[tex]\[ b \leq -2 \][/tex]

Therefore, the correct answer is:
A. [tex]\( b \leq -2 \)[/tex]
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