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Solve for [tex][tex]$x$[/tex][/tex]: [tex][tex]$-3x + 3 \ \textless \ 6$[/tex][/tex]

Sagot :

To solve the inequality [tex]\(-3x + 3 < 6\)[/tex] for [tex]\(x\)[/tex], follow these steps:

1. Start with the given inequality:
[tex]\[ -3x + 3 < 6 \][/tex]

2. Subtract 3 from both sides of the inequality to isolate the term involving [tex]\(x\)[/tex]:
[tex]\[ -3x + 3 - 3 < 6 - 3 \][/tex]
Simplifying the left and right sides gives:
[tex]\[ -3x < 3 \][/tex]

3. Divide both sides of the inequality by [tex]\(-3\)[/tex]. Remember, when you divide or multiply both sides of an inequality by a negative number, you must reverse the direction of the inequality sign:
[tex]\[ \frac{-3x}{-3} > \frac{3}{-3} \][/tex]
Simplifying this, we get:
[tex]\[ x > -1 \][/tex]

Thus, the solution to the inequality [tex]\(-3x + 3 < 6\)[/tex] is:
[tex]\[ x > -1 \][/tex]