Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Let's determine which equation models the relationship between the time [tex]\( t \)[/tex] in minutes and the quarts of water [tex]\( w \)[/tex] left in the tub.
From the problem, we know the following:
- The tub initially has 50 quarts of water.
- The tub empties at a rate of 2.5 quarts per minute.
We can use these pieces of information to form a linear equation.
When [tex]\( t = 0 \)[/tex], the initial amount of water [tex]\( w \)[/tex] is 50 quarts. Therefore, we start with the point (0, 50).
For every minute that passes, the water decreases by 2.5 quarts. This tells us the water [tex]\( w \)[/tex] will be impacted by the rate over time.
A linear relationship can be expressed as:
[tex]\[ w = w_{initial} - (rate \times t) \][/tex]
Substituting the given values:
[tex]\[ w = 50 - 2.5t \][/tex]
This equation [tex]\( w = 50 - 2.5t \)[/tex] correctly models the situation.
To find the solution when [tex]\( t = 30 \)[/tex] minutes, we can substitute [tex]\( t \)[/tex] with 30 into our equation:
[tex]\[ w = 50 - 2.5t \][/tex]
Substituting [tex]\( t = 30 \)[/tex]:
[tex]\[ w = 50 - 2.5 \times 30 \][/tex]
[tex]\[ w = 50 - 75 \][/tex]
[tex]\[ w = -25 \][/tex]
Therefore, when [tex]\( t = 30 \)[/tex] minutes, the amount of water left in the tub is [tex]\( -25 \)[/tex] quarts.
So, the correct equation that models the relationship is:
[tex]\[ w = 50 - 2.5t \][/tex]
The solution when the time is 30 minutes is:
[tex]\[ w = -25 \text{ quarts} \][/tex]
From the problem, we know the following:
- The tub initially has 50 quarts of water.
- The tub empties at a rate of 2.5 quarts per minute.
We can use these pieces of information to form a linear equation.
When [tex]\( t = 0 \)[/tex], the initial amount of water [tex]\( w \)[/tex] is 50 quarts. Therefore, we start with the point (0, 50).
For every minute that passes, the water decreases by 2.5 quarts. This tells us the water [tex]\( w \)[/tex] will be impacted by the rate over time.
A linear relationship can be expressed as:
[tex]\[ w = w_{initial} - (rate \times t) \][/tex]
Substituting the given values:
[tex]\[ w = 50 - 2.5t \][/tex]
This equation [tex]\( w = 50 - 2.5t \)[/tex] correctly models the situation.
To find the solution when [tex]\( t = 30 \)[/tex] minutes, we can substitute [tex]\( t \)[/tex] with 30 into our equation:
[tex]\[ w = 50 - 2.5t \][/tex]
Substituting [tex]\( t = 30 \)[/tex]:
[tex]\[ w = 50 - 2.5 \times 30 \][/tex]
[tex]\[ w = 50 - 75 \][/tex]
[tex]\[ w = -25 \][/tex]
Therefore, when [tex]\( t = 30 \)[/tex] minutes, the amount of water left in the tub is [tex]\( -25 \)[/tex] quarts.
So, the correct equation that models the relationship is:
[tex]\[ w = 50 - 2.5t \][/tex]
The solution when the time is 30 minutes is:
[tex]\[ w = -25 \text{ quarts} \][/tex]
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.