Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
To find the value of the expression [tex]\(\frac{j^3 k}{h^0}\)[/tex], we need to follow these steps:
1. Evaluate [tex]\(j^3\)[/tex]:
- Given [tex]\(j = -1\)[/tex], we calculate [tex]\(j^3\)[/tex].
[tex]\[ j^3 = (-1)^3 = -1 \][/tex]
2. Multiply [tex]\(j^3\)[/tex] by [tex]\(k\)[/tex]:
- Given [tex]\(k = -12\)[/tex], we use the result from step 1.
[tex]\[ j^3 \cdot k = (-1) \cdot (-12) = 12 \][/tex]
3. Evaluate [tex]\(h^0\)[/tex]:
- Given [tex]\(h = 8\)[/tex], recall that any number raised to the power of 0 is 1.
[tex]\[ h^0 = 1 \][/tex]
4. Divide the result from step 2 by the result from step 3:
[tex]\[ \frac{j^3 \cdot k}{h^0} = \frac{12}{1} = 12 \][/tex]
Therefore, the value of the expression [tex]\(\frac{j^3 k}{h^0}\)[/tex] is 12.
The correct answer is:
A. 12
1. Evaluate [tex]\(j^3\)[/tex]:
- Given [tex]\(j = -1\)[/tex], we calculate [tex]\(j^3\)[/tex].
[tex]\[ j^3 = (-1)^3 = -1 \][/tex]
2. Multiply [tex]\(j^3\)[/tex] by [tex]\(k\)[/tex]:
- Given [tex]\(k = -12\)[/tex], we use the result from step 1.
[tex]\[ j^3 \cdot k = (-1) \cdot (-12) = 12 \][/tex]
3. Evaluate [tex]\(h^0\)[/tex]:
- Given [tex]\(h = 8\)[/tex], recall that any number raised to the power of 0 is 1.
[tex]\[ h^0 = 1 \][/tex]
4. Divide the result from step 2 by the result from step 3:
[tex]\[ \frac{j^3 \cdot k}{h^0} = \frac{12}{1} = 12 \][/tex]
Therefore, the value of the expression [tex]\(\frac{j^3 k}{h^0}\)[/tex] is 12.
The correct answer is:
A. 12
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.