Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Sure, let's solve the problems step-by-step:
### Question 5
We need to compute the value of [tex]\( (67)^2 - (33)^2 \)[/tex].
To simplify this expression, we can use the difference of squares formula, which states:
[tex]\[ a^2 - b^2 = (a - b)(a + b) \][/tex]
Here, [tex]\( a = 67 \)[/tex] and [tex]\( b = 33 \)[/tex].
Using the formula:
[tex]\[ (67)^2 - (33)^2 = (67 - 33)(67 + 33) \][/tex]
First, calculate the difference:
[tex]\[ 67 - 33 = 34 \][/tex]
Next, calculate the sum:
[tex]\[ 67 + 33 = 100 \][/tex]
Now multiply these two results:
[tex]\[ 34 \times 100 = 3400 \][/tex]
So, the value of [tex]\( (67)^2 - (33)^2 \)[/tex] is [tex]\( 3400 \)[/tex].
Therefore, the answer to Question 5 is:
[tex]\[ \boxed{3400} \][/tex]
### Question 6
Given that [tex]\(-1\)[/tex] is a zero of the polynomial [tex]\( p(x) = a x^3 - x^2 + x + 4 \)[/tex], we need to find the value of [tex]\( a \)[/tex].
A zero of a polynomial means that if we substitute [tex]\(-1\)[/tex] into the polynomial, the result should be zero:
[tex]\[ p(-1) = 0 \][/tex]
Substitute [tex]\(-1\)[/tex] into [tex]\( p(x) \)[/tex]:
[tex]\[ p(-1) = a(-1)^3 - (-1)^2 + (-1) + 4 \][/tex]
Simplify step-by-step:
[tex]\[ p(-1) = a(-1) - 1 + (-1) + 4 \][/tex]
[tex]\[ p(-1) = -a - 1 - 1 + 4 \][/tex]
[tex]\[ p(-1) = -a + 2 \][/tex]
We know that:
[tex]\[ p(-1) = 0 \][/tex]
So:
[tex]\[ -a + 2 = 0 \][/tex]
Solve for [tex]\( a \)[/tex]:
[tex]\[ -a + 2 = 0 \][/tex]
[tex]\[ -a = -2 \][/tex]
[tex]\[ a = 2 \][/tex]
Therefore, the value of [tex]\( a \)[/tex] is:
[tex]\[ \boxed{2} \][/tex]
So, combining:
- The value of [tex]\( (67)^2 - (33)^2 \)[/tex] is [tex]\( 3400 \)[/tex].
- If [tex]\(-1\)[/tex] is a zero of the polynomial [tex]\( p(x) = a x^3 - x^2 + x + 4 \)[/tex], the value of [tex]\( a \)[/tex] is [tex]\( 2 \)[/tex].
### Question 5
We need to compute the value of [tex]\( (67)^2 - (33)^2 \)[/tex].
To simplify this expression, we can use the difference of squares formula, which states:
[tex]\[ a^2 - b^2 = (a - b)(a + b) \][/tex]
Here, [tex]\( a = 67 \)[/tex] and [tex]\( b = 33 \)[/tex].
Using the formula:
[tex]\[ (67)^2 - (33)^2 = (67 - 33)(67 + 33) \][/tex]
First, calculate the difference:
[tex]\[ 67 - 33 = 34 \][/tex]
Next, calculate the sum:
[tex]\[ 67 + 33 = 100 \][/tex]
Now multiply these two results:
[tex]\[ 34 \times 100 = 3400 \][/tex]
So, the value of [tex]\( (67)^2 - (33)^2 \)[/tex] is [tex]\( 3400 \)[/tex].
Therefore, the answer to Question 5 is:
[tex]\[ \boxed{3400} \][/tex]
### Question 6
Given that [tex]\(-1\)[/tex] is a zero of the polynomial [tex]\( p(x) = a x^3 - x^2 + x + 4 \)[/tex], we need to find the value of [tex]\( a \)[/tex].
A zero of a polynomial means that if we substitute [tex]\(-1\)[/tex] into the polynomial, the result should be zero:
[tex]\[ p(-1) = 0 \][/tex]
Substitute [tex]\(-1\)[/tex] into [tex]\( p(x) \)[/tex]:
[tex]\[ p(-1) = a(-1)^3 - (-1)^2 + (-1) + 4 \][/tex]
Simplify step-by-step:
[tex]\[ p(-1) = a(-1) - 1 + (-1) + 4 \][/tex]
[tex]\[ p(-1) = -a - 1 - 1 + 4 \][/tex]
[tex]\[ p(-1) = -a + 2 \][/tex]
We know that:
[tex]\[ p(-1) = 0 \][/tex]
So:
[tex]\[ -a + 2 = 0 \][/tex]
Solve for [tex]\( a \)[/tex]:
[tex]\[ -a + 2 = 0 \][/tex]
[tex]\[ -a = -2 \][/tex]
[tex]\[ a = 2 \][/tex]
Therefore, the value of [tex]\( a \)[/tex] is:
[tex]\[ \boxed{2} \][/tex]
So, combining:
- The value of [tex]\( (67)^2 - (33)^2 \)[/tex] is [tex]\( 3400 \)[/tex].
- If [tex]\(-1\)[/tex] is a zero of the polynomial [tex]\( p(x) = a x^3 - x^2 + x + 4 \)[/tex], the value of [tex]\( a \)[/tex] is [tex]\( 2 \)[/tex].
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.