At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
To balance the combustion reaction of octane, [tex]\( C_8H_{18} \)[/tex], with oxygen, [tex]\( O_2 \)[/tex], into carbon dioxide, [tex]\( CO_2 \)[/tex], and water, [tex]\( H_2O \)[/tex], we need to ensure that we have the same number of each type of atom on both sides of the equation. Here is the step-by-step process to balance the equation:
1. Write the unbalanced equation:
[tex]\[ C_8H_{18} + O_2 \rightarrow \_ CO_2 + \_ H_2O \][/tex]
2. Balance the number of carbon (C) atoms:
- There are 8 carbon atoms in [tex]\( C_8H_{18} \)[/tex].
- We need 8 carbon atoms in the products, which will be in the form of [tex]\( CO_2 \)[/tex].
- Therefore, the coefficient for [tex]\( CO_2 \)[/tex] will be 8:
[tex]\[ C_8H_{18} + O_2 \rightarrow 8 CO_2 + \_ H_2O \][/tex]
3. Balance the number of hydrogen (H) atoms:
- There are 18 hydrogen atoms in [tex]\( C_8H_{18} \)[/tex].
- Water ([tex]\( H_2O \)[/tex]) contains 2 hydrogen atoms per molecule.
- To balance 18 hydrogen atoms, we need [tex]\( \frac{18}{2} = 9 \)[/tex] water molecules:
[tex]\[ C_8H_{18} + O_2 \rightarrow 8 CO_2 + 9 H_2O \][/tex]
4. Balance the number of oxygen (O) atoms:
- On the right-hand side, we have:
- [tex]\( 8 CO_2 \)[/tex] molecules, each providing 2 oxygen atoms, totaling [tex]\( 8 \times 2 = 16 \)[/tex] oxygen atoms.
- [tex]\( 9 H_2O \)[/tex] molecules, each providing 1 oxygen atom, totaling 9 oxygen atoms.
- Therefore, the total number of oxygen atoms on the right-hand side is [tex]\( 16 + 9 = 25 \)[/tex].
- Oxygen ([tex]\( O_2 \)[/tex]) contains 2 oxygen atoms per molecule.
- To balance 25 oxygen atoms, we need [tex]\( \frac{25}{2} = 12.5 \)[/tex] oxygen molecules:
[tex]\[ C_8H_{18} + 12.5 O_2 \rightarrow 8 CO_2 + 9 H_2O \][/tex]
5. Avoid fractions by multiplying the entire equation by 2:
- This will give us whole numbers for all coefficients:
[tex]\[ 2 C_8H_{18} + 25 O_2 \rightarrow 16 CO_2 + 18 H_2O \][/tex]
Thus, the balanced combustion reaction for octane, [tex]\( C_8H_{18} \)[/tex], is:
[tex]\[ 2 C_8H_{18} + 25 O_2 \rightarrow 16 CO_2 + 18 H_2O \][/tex]
In this balanced equation, the coefficients are:
- [tex]\( C_8H_{18} \)[/tex]: 2
- [tex]\( O_2 \)[/tex]: 25
- [tex]\( CO_2 \)[/tex]: 16
- [tex]\( H_2O \)[/tex]: 18
So, the coefficients for the balanced equation are:
[tex]\[ [2, 25, 16, 18] \][/tex]
1. Write the unbalanced equation:
[tex]\[ C_8H_{18} + O_2 \rightarrow \_ CO_2 + \_ H_2O \][/tex]
2. Balance the number of carbon (C) atoms:
- There are 8 carbon atoms in [tex]\( C_8H_{18} \)[/tex].
- We need 8 carbon atoms in the products, which will be in the form of [tex]\( CO_2 \)[/tex].
- Therefore, the coefficient for [tex]\( CO_2 \)[/tex] will be 8:
[tex]\[ C_8H_{18} + O_2 \rightarrow 8 CO_2 + \_ H_2O \][/tex]
3. Balance the number of hydrogen (H) atoms:
- There are 18 hydrogen atoms in [tex]\( C_8H_{18} \)[/tex].
- Water ([tex]\( H_2O \)[/tex]) contains 2 hydrogen atoms per molecule.
- To balance 18 hydrogen atoms, we need [tex]\( \frac{18}{2} = 9 \)[/tex] water molecules:
[tex]\[ C_8H_{18} + O_2 \rightarrow 8 CO_2 + 9 H_2O \][/tex]
4. Balance the number of oxygen (O) atoms:
- On the right-hand side, we have:
- [tex]\( 8 CO_2 \)[/tex] molecules, each providing 2 oxygen atoms, totaling [tex]\( 8 \times 2 = 16 \)[/tex] oxygen atoms.
- [tex]\( 9 H_2O \)[/tex] molecules, each providing 1 oxygen atom, totaling 9 oxygen atoms.
- Therefore, the total number of oxygen atoms on the right-hand side is [tex]\( 16 + 9 = 25 \)[/tex].
- Oxygen ([tex]\( O_2 \)[/tex]) contains 2 oxygen atoms per molecule.
- To balance 25 oxygen atoms, we need [tex]\( \frac{25}{2} = 12.5 \)[/tex] oxygen molecules:
[tex]\[ C_8H_{18} + 12.5 O_2 \rightarrow 8 CO_2 + 9 H_2O \][/tex]
5. Avoid fractions by multiplying the entire equation by 2:
- This will give us whole numbers for all coefficients:
[tex]\[ 2 C_8H_{18} + 25 O_2 \rightarrow 16 CO_2 + 18 H_2O \][/tex]
Thus, the balanced combustion reaction for octane, [tex]\( C_8H_{18} \)[/tex], is:
[tex]\[ 2 C_8H_{18} + 25 O_2 \rightarrow 16 CO_2 + 18 H_2O \][/tex]
In this balanced equation, the coefficients are:
- [tex]\( C_8H_{18} \)[/tex]: 2
- [tex]\( O_2 \)[/tex]: 25
- [tex]\( CO_2 \)[/tex]: 16
- [tex]\( H_2O \)[/tex]: 18
So, the coefficients for the balanced equation are:
[tex]\[ [2, 25, 16, 18] \][/tex]
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.