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Find the y-intercept of the equation: [tex]\( y = -10 + 3x \)[/tex]

A. [tex]\((0, -10)\)[/tex]
B. [tex]\((0, \frac{10}{3})\)[/tex]
C. [tex]\((0, 10)\)[/tex]
D. [tex]\((0, -\frac{10}{3})\)[/tex]

Sagot :

GinnyAnswer
To find the [tex]$y$[/tex]-intercept of the equation [tex]\( y = -10 + 3x \)[/tex], we need to determine the value of [tex]\( y \)[/tex] when [tex]\( x = 0 \)[/tex].

Step-by-step:

1. Start with the given equation:
[tex]\[ y = -10 + 3x \][/tex]

2. Substitute [tex]\( x = 0 \)[/tex] into the equation:
[tex]\[ y = -10 + 3(0) \][/tex]

3. Simplify the equation:
[tex]\[ y = -10 + 0 \][/tex]

4. This simplifies further to:
[tex]\[ y = -10 \][/tex]

Hence, the [tex]$y$[/tex]-intercept, where [tex]\( x = 0 \)[/tex], is:
[tex]\[ (0, -10) \][/tex]

Among the given options:
- [tex]\((0, -10)\)[/tex]
- [tex]\((0, 10/3)\)[/tex]
- [tex]\((0, 10)\)[/tex]
- [tex]\((0, -10/3)\)[/tex]

The correct option is:
[tex]\[ \boxed{(0, -10)} \][/tex]
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