awoseyilabunmi
Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

6. Huey, Dewey, and Louie work at a bank. Each day, one of them is randomly selected to be a greeter for customers. Over two consecutive days, which event is least likely to occur? Show the probability as proof.

A. Dewey is not assigned at all.
B. Louie is assigned at least once.
C. Huey is assigned exactly once.
D. The same person is assigned twice.

Sagot :

GinnyAnswer

Final answer:

The solution calculates the least likely event over two consecutive days at a bank based on the given probabilities.


Explanation:

To determine the least likely event over two consecutive days:

  1. Dewey not being assigned at all: Probability = (2/3) (2/3) = 4/9 = 0.444.
  2. Louie being assigned at least once: Probability = 1 - (1/3 1/3) = 8/9 = 0.888.
  3. Huey being assigned exactly once: Probability = (1/3 2/3) + (2/3 1/3) = 4/9 = 0.444.
  4. The same person being assigned twice: Probability = (1/3 1/3) + (1/3 1/3) = 2/9 = 0.222.

Therefore, the event least likely to occur over two consecutive days is Dewey not being assigned at all with a probability of 0.444.


Learn more about Probability and Events here:

https://brainly.com/question/17089724


Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.