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Which of the following is the solution to the compound inequality below?

[tex]\[
5 + x \geq 3 \text{ or } 6x + 1 \ \textless \ -29
\][/tex]

A. [tex]\( x \geq -2 \)[/tex] or [tex]\( x \ \textless \ -5 \)[/tex]
B. [tex]\( x \geq 8 \)[/tex] or [tex]\( x \ \textless \ \frac{14}{3} \)[/tex]
C. [tex]\( x \geq -\frac{3}{5} \)[/tex] or [tex]\( x \ \textless \ -\frac{14}{3} \)[/tex]
D. [tex]\( x \geq 2 \)[/tex] or [tex]\( x \ \textless \ 5 \)[/tex]


Sagot :

To determine the solution to the compound inequality [tex]\( 5 + x \geq 3 \)[/tex] or [tex]\( 6x + 1 < -29 \)[/tex], let's break it down into two parts and solve each part separately.

### Solving the first part: [tex]\( 5 + x \geq 3 \)[/tex]

1. Start with the inequality:
[tex]\[ 5 + x \geq 3 \][/tex]

2. Subtract 5 from both sides to isolate [tex]\( x \)[/tex]:
[tex]\[ x \geq 3 - 5 \][/tex]

3. Simplify:
[tex]\[ x \geq -2 \][/tex]

### Solving the second part: [tex]\( 6x + 1 < -29 \)[/tex]

1. Start with the inequality:
[tex]\[ 6x + 1 < -29 \][/tex]

2. Subtract 1 from both sides to isolate the term with [tex]\( x \)[/tex]:
[tex]\[ 6x < -29 - 1 \][/tex]

3. Simplify:
[tex]\[ 6x < -30 \][/tex]

4. Divide both sides by 6 to solve for [tex]\( x \)[/tex]:
[tex]\[ x < -30 / 6 \][/tex]

5. Simplify:
[tex]\[ x < -5 \][/tex]

### Combining the Solutions

The solution to the compound inequality [tex]\( 5 + x \geq 3 \)[/tex] or [tex]\( 6x + 1 < -29 \)[/tex] is the union of the solutions to each individual inequality.

- From the first part: [tex]\( x \geq -2 \)[/tex]
- From the second part: [tex]\( x < -5 \)[/tex]

Thus, the combined solution is:
[tex]\[ x \geq -2 \text{ or } x < -5 \][/tex]

Therefore, the correct choice is:
[tex]\[ A. \, x \geq -2 \text{ or } x < -5 \][/tex]
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