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Given [tex]\( h(t) = -2(t + 5)^2 + 4 \)[/tex], find [tex]\( h(-8) \)[/tex].

A. [tex]\(-334\)[/tex]
B. [tex]\(-14\)[/tex]
C. 45
D. 445


Sagot :

To find [tex]\( h(-8) \)[/tex] given the function [tex]\( h(t) = -2(t+5)^2 + 4 \)[/tex], we will follow these steps:

1. Substitute [tex]\( t = -8 \)[/tex] into the function:
[tex]\[ h(-8) = -2(-8+5)^2 + 4 \][/tex]

2. Simplify inside the parentheses:
[tex]\[ -8 + 5 = -3 \][/tex]
Thus,
[tex]\[ h(-8) = -2(-3)^2 + 4 \][/tex]

3. Square the value inside the parentheses:
[tex]\[ (-3)^2 = 9 \][/tex]
So the equation becomes:
[tex]\[ h(-8) = -2 \cdot 9 + 4 \][/tex]

4. Multiply [tex]\(-2\)[/tex] by [tex]\( 9 \)[/tex]:
[tex]\[ -2 \cdot 9 = -18 \][/tex]
Now the equation is:
[tex]\[ h(-8) = -18 + 4 \][/tex]

5. Add [tex]\( 4 \)[/tex] to [tex]\(-18\)[/tex]:
[tex]\[ -18 + 4 = -14 \][/tex]

Hence, [tex]\( h(-8) = -14 \)[/tex].

Therefore, the correct answer is:
[tex]\[ \boxed{-14} \][/tex]