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What is the lenth of the diagonal of a 10cm by 115cm rectangle?

Sagot :

Answer:

x = 115.4

Step-by-step explanation:

Let x be the diagonal of the rectangle and hypotenuse of the triangle.

Using Pythagoras' Theorem,

hypotenuse² = opposite ² + adjacent²

x² = 10² + 115²

x² = 100 + 13225

x² = 13, 325 Take the square roots of both sides

x = √13,325

x = 115.4339638

x = 115.4 to the nearest tenth

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