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Complete the table of values:

[tex]\[
\begin{tabular}{|c|c|}
\hline
$x$ & $4^{-x}$ \\
\hline
-1 & 4 \\
\hline
0 & $a$ \\
\hline
2 & $b$ \\
\hline
4 & $c$ \\
\hline
\end{tabular}
\][/tex]

[tex]\[
\begin{array}{ll}
a = \square & b = \square \\
c = \square
\end{array}
\][/tex]

Sagot :

GinnyAnswer
Let's complete the table of values step-by-step.

Given:
[tex]\[ \begin{array}{|c|c|} \hline x & 4^{-x} \\ \hline -1 & 4 \\ \hline 0 & a \\ \hline 2 & b \\ \hline 4 & c \\ \hline \end{array} \][/tex]

We need to find the values of [tex]\( a \)[/tex], [tex]\( b \)[/tex], and [tex]\( c \)[/tex].

For [tex]\( x = 0 \)[/tex]:
[tex]\[ 4^{-x} = 4^0 \][/tex]
Anything raised to the power of 0 is 1, so:
[tex]\[ a = 4^0 = 1 \][/tex]

For [tex]\( x = 2 \)[/tex]:
[tex]\[ 4^{-x} = 4^{-2} \][/tex]
[tex]\[ b = 4^{-2} = \frac{1}{4^2} = \frac{1}{16} = 0.0625 \][/tex]

For [tex]\( x = 4 \)[/tex]:
[tex]\[ 4^{-x} = 4^{-4} \][/tex]
[tex]\[ c = 4^{-4} = \frac{1}{4^4} = \frac{1}{256} = 0.00390625 \][/tex]

So the complete table is:
[tex]\[ \begin{array}{|c|c|} \hline x & 4^{-x} \\ \hline -1 & 4 \\ \hline 0 & 1 \\ \hline 2 & 0.0625 \\ \hline 4 & 0.00390625 \\ \hline \end{array} \][/tex]

Therefore:
[tex]\[ a = 1, \quad b = 0.0625, \quad c = 0.00390625 \][/tex]
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