Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Find the maximum value of [tex]\(\delta \ \textgreater \ 0\)[/tex] that satisfies the limit claim corresponding to [tex]\(\varepsilon = 0.4\)[/tex], such that [tex]\(0 \ \textless \ |x - c| \ \textless \ \delta\)[/tex] implies [tex]\(|f(x) - L| \ \textless \ 0.4\)[/tex].

Given:
[tex]\[
\lim _{x \rightarrow 4}\left(5 - \frac{x}{2}\right) = 3
\][/tex]


Sagot :

To solve the problem, we need to determine the maximum value of [tex]\(\delta > 0\)[/tex] that ensures the function [tex]\(f(x) = 5 - \frac{x}{2}\)[/tex] remains within [tex]\(\varepsilon = 0.4\)[/tex] of the limit [tex]\(L = 3\)[/tex] when [tex]\(x\)[/tex] is within [tex]\(\delta\)[/tex] units of [tex]\(c = 4\)[/tex].

### Step-by-Step Solution

1. Determine the function's form:
The function given is [tex]\(f(x) = 5 - \frac{x}{2}\)[/tex].

2. Restate the limit property:
We want to find a [tex]\(\delta > 0\)[/tex] such that for all [tex]\(x\)[/tex] satisfying [tex]\(0 < |x - 4| < \delta\)[/tex] (i.e., [tex]\(x\)[/tex] is within [tex]\(\delta\)[/tex] units of 4), the following inequality holds:
[tex]\[ |(5 - \frac{x}{2}) - 3| < 0.4. \][/tex]

3. Simplify the absolute value expression:
Rewrite the expression inside the absolute value:
[tex]\[ |(5 - \frac{x}{2}) - 3| = |2 - \frac{x}{2}|. \][/tex]

4. Set up the inequality:
Now, we need to solve the inequality:
[tex]\[ |2 - \frac{x}{2}| < 0.4. \][/tex]

5. Solve for [tex]\(x\)[/tex]:
Convert the absolute value inequality into a double inequality:
[tex]\[ -0.4 < 2 - \frac{x}{2} < 0.4. \][/tex]

6. Isolate [tex]\(x\)[/tex] on both sides:
Solve each part of the inequality separately:

- For the left side:
[tex]\[ -0.4 < 2 - \frac{x}{2} \][/tex]
[tex]\[ -2.4 < -\frac{x}{2} \][/tex]
Multiply through by -2 (note that this reverses the inequality):
[tex]\[ 4.8 > x \quad \text{or} \quad x < 4.8. \][/tex]

- For the right side:
[tex]\[ 2 - \frac{x}{2} < 0.4 \][/tex]
[tex]\[ 1.6 < \frac{x}{2} \][/tex]
Multiply through by 2:
[tex]\[ 3.2 < x \quad \text{or} \quad x > 3.2. \][/tex]

7. Combine the results:
Combining both parts, we get:
[tex]\[ 3.2 < x < 4.8. \][/tex]

8. Relate to [tex]\(\delta\)[/tex]:
We need [tex]\(0 < |x - 4| < \delta\)[/tex]. From the bounds calculated, we observe the maximum deviation from 4 is from either end of the interval [tex]\(3.2\)[/tex] and [tex]\(4.8\)[/tex]:

- From 4:
[tex]\[ 4 - 3.2 = 0.8 \][/tex]
[tex]\[ 4.8 - 4 = 0.8. \][/tex]

So, the maximum [tex]\(\delta\)[/tex] that satisfies the condition is:

[tex]\[ \boxed{0.8} \][/tex]
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.