Answered

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3. Given [tex]\( k = \frac{1}{2} \)[/tex]

[tex]\[
\begin{array}{l}
(6,6) \ \textgreater \ (1, \\
(4,6))_r(-1
\end{array}
\][/tex]

Sagot :

GinnyAnswer
Sure! Let's solve the question step-by-step.

Given:
1. [tex]\( k = \frac{1}{2} \)[/tex]
2. We have two ordered pairs: [tex]\((6, 6)\)[/tex] and [tex]\((4, 6)\)[/tex].

Solution:

1. Value of [tex]\( k \)[/tex]:
- The problem gives [tex]\( k = \frac{1}{2} \)[/tex].

2. Comparing the ordered pairs [tex]\((6, 6)\)[/tex] and [tex]\((4, 6)\)[/tex]:
- In mathematics, when comparing ordered pairs [tex]\((a, b)\)[/tex] and [tex]\((c, d)\)[/tex], we start by comparing the first elements of each pair. If [tex]\( a > c \)[/tex], then [tex]\((a, b) > (c, d)\)[/tex].

- Here, we compare the first elements of the pairs:
- The first element of the first pair is 6.
- The first element of the second pair is 4.

3. Conclusion:
- Since 6 > 4, the ordered pair [tex]\((6, 6)\)[/tex] is greater than the ordered pair [tex]\((4, 6)\)[/tex].

So, the detailed answer incorporating these steps is:
- The value of [tex]\( k \)[/tex] is [tex]\( 0.5 \)[/tex].
- Comparing the ordered pairs, we find that [tex]\((6, 6)\)[/tex] is greater than [tex]\((4, 6)\)[/tex].

The final result is:
- [tex]\( k = 0.5 \)[/tex]
- The comparison result is True.
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