At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
To find [tex]\((f+g)(x)\)[/tex] for the given functions [tex]\( f \)[/tex] and [tex]\( g \)[/tex], follow these steps:
1. Identify the functions [tex]\( f \)[/tex] and [tex]\( g \)[/tex]:
[tex]\[ f(x) = 2x + 7 \][/tex]
[tex]\[ g(x) = 7x - 4 \][/tex]
2. Add the functions [tex]\( f \)[/tex] and [tex]\( g \)[/tex]:
[tex]\[ (f+g)(x) = f(x) + g(x) \][/tex]
3. Substitute the expressions for [tex]\( f(x) \)[/tex] and [tex]\( g(x) \)[/tex]:
[tex]\[ (f+g)(x) = (2x + 7) + (7x - 4) \][/tex]
4. Combine like terms:
[tex]\[ (f+g)(x) = 2x + 7x + 7 - 4 \][/tex]
5. Simplify the expression:
[tex]\[ (f+g)(x) = (2x + 7x) + (7 - 4) \][/tex]
[tex]\[ (f+g)(x) = 9x + 3 \][/tex]
So, the simplified form of [tex]\((f+g)(x)\)[/tex] is:
[tex]\[ (f+g)(x) = 9x + 3 \][/tex]
1. Identify the functions [tex]\( f \)[/tex] and [tex]\( g \)[/tex]:
[tex]\[ f(x) = 2x + 7 \][/tex]
[tex]\[ g(x) = 7x - 4 \][/tex]
2. Add the functions [tex]\( f \)[/tex] and [tex]\( g \)[/tex]:
[tex]\[ (f+g)(x) = f(x) + g(x) \][/tex]
3. Substitute the expressions for [tex]\( f(x) \)[/tex] and [tex]\( g(x) \)[/tex]:
[tex]\[ (f+g)(x) = (2x + 7) + (7x - 4) \][/tex]
4. Combine like terms:
[tex]\[ (f+g)(x) = 2x + 7x + 7 - 4 \][/tex]
5. Simplify the expression:
[tex]\[ (f+g)(x) = (2x + 7x) + (7 - 4) \][/tex]
[tex]\[ (f+g)(x) = 9x + 3 \][/tex]
So, the simplified form of [tex]\((f+g)(x)\)[/tex] is:
[tex]\[ (f+g)(x) = 9x + 3 \][/tex]
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.