Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Complete the table based on the given domain: [tex]\(\{-12, -6, 3, 15\}\)[/tex]

Given function: [tex]\( y = -\frac{2}{3}x + 7 \)[/tex]

[tex]\[
\begin{tabular}{|c|c|}
\hline
$x$ & $y$ \\
\hline
-6 & $\square$ \\
\hline
$\square$ & 5 \\
\hline
15 & $\square$ \\
\hline
$\square$ & 15 \\
\hline
\end{tabular}
\][/tex]

Sagot :

GinnyAnswer
To complete the table for the given linear function [tex]\( y = -\frac{2}{3}x + 7 \)[/tex] and domain [tex]\( \{-12, -6, 3, 15\} \)[/tex]:

1. When [tex]\( x = -6 \)[/tex]:
Calculate [tex]\( y \)[/tex] when [tex]\( x = -6 \)[/tex].

Result: [tex]\( y = 11.0 \)[/tex]

2. When [tex]\( y = 5 \)[/tex]:
Find [tex]\( x \)[/tex] such that [tex]\( y = 5 \)[/tex].

Result: [tex]\( x = 3.0 \)[/tex]

3. When [tex]\( x = 15 \)[/tex]:
Calculate [tex]\( y \)[/tex] when [tex]\( x = 15 \)[/tex].

Result: [tex]\( y = -3.0 \)[/tex]

4. When [tex]\( y = 15 \)[/tex]:
Find [tex]\( x \)[/tex] such that [tex]\( y = 15 \)[/tex].

Result: [tex]\( x = -12.0 \)[/tex]

So, the completed table is:

[tex]\[ \begin{tabular}{|c|c|} \hline $x$ & $y$ \\ \hline -6 & 11.0 \\ \hline 3.0 & 5 \\ \hline 15 & -3.0 \\ \hline -12.0 & 15 \\ \hline \end{tabular} \][/tex]
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.