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Sagot :
To find the width of the rectangle given its perimeter and length, we can follow a step-by-step process, using the formula for the perimeter of a rectangle.
The formula for the perimeter [tex]\( P \)[/tex] of a rectangle is given by:
[tex]\[ P = 2L + 2W \][/tex]
where [tex]\( L \)[/tex] is the length and [tex]\( W \)[/tex] is the width.
Given:
- The perimeter [tex]\( P \)[/tex] is 44 cm
- The length [tex]\( L \)[/tex] is 14 cm
We need to find the width [tex]\( W \)[/tex].
1. Start with the perimeter formula:
[tex]\[ 44 = 2 \times 14 + 2 \times W \][/tex]
2. Simplify the equation:
[tex]\[ 44 = 28 + 2 \times W \][/tex]
3. Subtract 28 from both sides to isolate the term with [tex]\( W \)[/tex]:
[tex]\[ 44 - 28 = 2 \times W \][/tex]
[tex]\[ 16 = 2 \times W \][/tex]
4. Divide both sides by 2 to solve for [tex]\( W \)[/tex]:
[tex]\[ W = \frac{16}{2} \][/tex]
[tex]\[ W = 8 \][/tex]
Therefore, the width of the rectangle is 8 cm. So, the correct answer is:
C. 8 cm
The formula for the perimeter [tex]\( P \)[/tex] of a rectangle is given by:
[tex]\[ P = 2L + 2W \][/tex]
where [tex]\( L \)[/tex] is the length and [tex]\( W \)[/tex] is the width.
Given:
- The perimeter [tex]\( P \)[/tex] is 44 cm
- The length [tex]\( L \)[/tex] is 14 cm
We need to find the width [tex]\( W \)[/tex].
1. Start with the perimeter formula:
[tex]\[ 44 = 2 \times 14 + 2 \times W \][/tex]
2. Simplify the equation:
[tex]\[ 44 = 28 + 2 \times W \][/tex]
3. Subtract 28 from both sides to isolate the term with [tex]\( W \)[/tex]:
[tex]\[ 44 - 28 = 2 \times W \][/tex]
[tex]\[ 16 = 2 \times W \][/tex]
4. Divide both sides by 2 to solve for [tex]\( W \)[/tex]:
[tex]\[ W = \frac{16}{2} \][/tex]
[tex]\[ W = 8 \][/tex]
Therefore, the width of the rectangle is 8 cm. So, the correct answer is:
C. 8 cm
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