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Sagot :
To find which school has the greater number of boys and by how many, let's break down the information step by step.
### Barlow School:
1. Total students: 873
2. Fraction of boys: [tex]\( \frac{4}{9} \)[/tex]
3. Number of boys:
[tex]\[ \text{Number of boys in Barlow School} = 873 \times \frac{4}{9} = 388.0 \][/tex]
### Willow School:
1. Total students: 630
2. Fraction of girls: [tex]\( \frac{2}{3} \)[/tex]
3. Number of girls:
[tex]\[ \text{Number of girls in Willow School} = 630 \times \frac{2}{3} = 420 \][/tex]
4. Number of boys:
[tex]\[ \text{Number of boys in Willow School} = \text{Total students} - \text{Number of girls} = 630 - 420 = 210.0 \][/tex]
### Comparison:
- Boys in Barlow School: 388.0
- Boys in Willow School: 210.0
### Conclusion:
- School with the greater number of boys: Barlow School
- Difference in the number of boys:
[tex]\[ \text{Difference} = 388.0 - 210.0 = 178.0 \][/tex]
Hence, Barlow School has the greater number of boys, and the difference is 178.0 boys.
### Barlow School:
1. Total students: 873
2. Fraction of boys: [tex]\( \frac{4}{9} \)[/tex]
3. Number of boys:
[tex]\[ \text{Number of boys in Barlow School} = 873 \times \frac{4}{9} = 388.0 \][/tex]
### Willow School:
1. Total students: 630
2. Fraction of girls: [tex]\( \frac{2}{3} \)[/tex]
3. Number of girls:
[tex]\[ \text{Number of girls in Willow School} = 630 \times \frac{2}{3} = 420 \][/tex]
4. Number of boys:
[tex]\[ \text{Number of boys in Willow School} = \text{Total students} - \text{Number of girls} = 630 - 420 = 210.0 \][/tex]
### Comparison:
- Boys in Barlow School: 388.0
- Boys in Willow School: 210.0
### Conclusion:
- School with the greater number of boys: Barlow School
- Difference in the number of boys:
[tex]\[ \text{Difference} = 388.0 - 210.0 = 178.0 \][/tex]
Hence, Barlow School has the greater number of boys, and the difference is 178.0 boys.
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