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Sagot :
To solve for [tex]\( i^3 \)[/tex] where [tex]\( i = \sqrt{-1} \)[/tex]:
1. Start by knowing the fundamental property of [tex]\( i \)[/tex], which is:
[tex]\[ i = \sqrt{-1} \][/tex]
2. Next, calculate [tex]\( i^2 \)[/tex]:
[tex]\[ i^2 = (\sqrt{-1})^2 = -1 \][/tex]
3. Now, use the value of [tex]\( i^2 \)[/tex] to find [tex]\( i^3 \)[/tex]:
[tex]\[ i^3 = i \cdot i^2 \][/tex]
4. Substitute [tex]\( i^2 \)[/tex] with [tex]\(-1\)[/tex]:
[tex]\[ i^3 = i \cdot (-1) = -i \][/tex]
So, the value of [tex]\( i^3 \)[/tex] is:
[tex]\[ -i \][/tex]
Therefore, [tex]\( i^3 \)[/tex] evaluates to [tex]\(-i\)[/tex]. Among the given choices, the correct answer is:
[tex]\[ \boxed{-i} \][/tex]
1. Start by knowing the fundamental property of [tex]\( i \)[/tex], which is:
[tex]\[ i = \sqrt{-1} \][/tex]
2. Next, calculate [tex]\( i^2 \)[/tex]:
[tex]\[ i^2 = (\sqrt{-1})^2 = -1 \][/tex]
3. Now, use the value of [tex]\( i^2 \)[/tex] to find [tex]\( i^3 \)[/tex]:
[tex]\[ i^3 = i \cdot i^2 \][/tex]
4. Substitute [tex]\( i^2 \)[/tex] with [tex]\(-1\)[/tex]:
[tex]\[ i^3 = i \cdot (-1) = -i \][/tex]
So, the value of [tex]\( i^3 \)[/tex] is:
[tex]\[ -i \][/tex]
Therefore, [tex]\( i^3 \)[/tex] evaluates to [tex]\(-i\)[/tex]. Among the given choices, the correct answer is:
[tex]\[ \boxed{-i} \][/tex]
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