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For each hour he babysits, Anderson earns [tex]$1 more than half of Carey's hourly rate. Anderson earns $[/tex]6 per hour. Which equation can be used to solve for Carey's hourly rate, [tex]\( c \)[/tex]?

A. [tex]\(\frac{1}{2}c + 1 = 6\)[/tex]

B. [tex]\(\frac{1}{2}c - 1 = 6\)[/tex]

C. [tex]\(\frac{1}{2}c + 6 = 1\)[/tex]

D. [tex]\(\frac{1}{2}c - 6 = 1\)[/tex]


Sagot :

To determine the equation that can be used to solve for Carey's hourly rate, [tex]\( c \)[/tex], we start by understanding the relationship between Anderson's and Carey's earnings.

According to the problem, Anderson earns \[tex]$6 per hour and this amount is \$[/tex]1 more than half of Carey's hourly rate. We need to translate this relationship into a mathematical equation.

Let's break it down step-by-step:

1. Carey's hourly rate is [tex]\( c \)[/tex].

2. Half of Carey's hourly rate is [tex]\(\frac{1}{2} c\)[/tex].

3. Anderson earns \[tex]$1 more than half of Carey's hourly rate. Therefore, we add 1 to half of Carey's rate: \[ \frac{1}{2} c + 1 \] 4. According to the problem, Anderson's hourly rate is \$[/tex]6. Therefore, we set up the equation:
[tex]\[ \frac{1}{2} c + 1 = 6 \][/tex]

Among the given options, the equation that represents this relationship is:
[tex]\[ \frac{1}{2} c + 1 = 6 \][/tex]

Thus, the correct equation to solve for Carey's hourly rate, [tex]\(c\)[/tex], is:
[tex]\[ \boxed{\frac{1}{2} c + 1 = 6} \][/tex]
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