Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Given the following functions, match each expression with its correct answer.

[tex]\[
\begin{array}{l}
f(x) = 3x^2 + 2 \\
g(x) = 4x^2 + 2x - 1 \\
h(x) = 2x - 3
\end{array}
\][/tex]


Sagot :

Let's solve each expression step by step to find their respective values.

1. Evaluate [tex]\( f(2) \)[/tex]:
[tex]\[ f(x) = 3x^2 + 2 \][/tex]
Substitute [tex]\( x = 2 \)[/tex]:
[tex]\[ f(2) = 3(2)^2 + 2 = 3(4) + 2 = 12 + 2 = 14 \][/tex]

2. Evaluate [tex]\( g(3) \)[/tex]:
[tex]\[ g(x) = 4x^2 + 2x - 1 \][/tex]
Substitute [tex]\( x = 3 \)[/tex]:
[tex]\[ g(3) = 4(3)^2 + 2(3) - 1 = 4(9) + 6 - 1 = 36 + 6 - 1 = 41 \][/tex]

3. Evaluate [tex]\( h(4) \)[/tex]:
[tex]\[ h(x) = 2x - 3 \][/tex]
Substitute [tex]\( x = 4 \)[/tex]:
[tex]\[ h(4) = 2(4) - 3 = 8 - 3 = 5 \][/tex]

4. Evaluate [tex]\( f(1) + g(1) \)[/tex]:
[tex]\[ f(x) = 3x^2 + 2,\quad g(x) = 4x^2 + 2x - 1 \][/tex]
Substitute [tex]\( x = 1 \)[/tex]:
[tex]\[ f(1) = 3(1)^2 + 2 = 3(1) + 2 = 3 + 2 = 5 \][/tex]
[tex]\[ g(1) = 4(1)^2 + 2(1) - 1 = 4(1) + 2(1) - 1 = 4 + 2 - 1 = 5 \][/tex]
[tex]\[ f(1) + g(1) = 5 + 5 = 10 \][/tex]

5. Evaluate [tex]\( h(2) + f(2) \)[/tex]:
[tex]\[ h(x) = 2x - 3,\quad f(x) = 3x^2 + 2 \][/tex]
Substitute [tex]\( x = 2 \)[/tex]:
[tex]\[ h(2) = 2(2) - 3 = 4 - 3 = 1 \][/tex]
[tex]\[ f(2) = 3(2)^2 + 2 = 3(4) + 2 = 12 + 2 = 14 \][/tex]
[tex]\[ h(2) + f(2) = 1 + 14 = 15 \][/tex]

Finally, let's match the expressions with their results:
[tex]\[ \begin{array}{l} f(2) = 14 \\ g(3) = 41 \\ h(4) = 5 \\ f(1) + g(1) = 10 \\ h(2) + f(2) = 15 \\ \end{array} \][/tex]

Thus, the correct answers to the given functions are:
[tex]\[ \begin{array}{l} f(2) = 14 \\ g(3) = 41 \\ h(4) = 5 \\ f(1) + g(1) = 10 \\ h(2) + f(2) = 15 \\ \end{array} \][/tex]