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Two points located on [tex]\(\overleftrightarrow{JK}\)[/tex] are [tex]\(J(6,1)\)[/tex] and [tex]\(K(-3,8)\)[/tex]. What is the slope of [tex]\(\overleftrightarrow{JK}\)[/tex]?

A. [tex]\(-\frac{9}{7}\)[/tex]

B. [tex]\(-\frac{7}{9}\)[/tex]

C. [tex]\(\frac{7}{9}\)[/tex]

D. [tex]\(\frac{9}{7}\)[/tex]

Sagot :

GinnyAnswer
To find the slope of the line passing through the points [tex]\( J(6, 1) \)[/tex] and [tex]\( K(-3, 8) \)[/tex], we will use the slope formula:
[tex]\[ \text{slope} = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]

Here, the coordinates of point [tex]\( J \)[/tex] are [tex]\((x_1, y_1) = (6, 1)\)[/tex], and the coordinates of point [tex]\( K \)[/tex] are [tex]\((x_2, y_2) = (-3, 8)\)[/tex].

Substituting these values into the slope formula gives:
[tex]\[ \text{slope} = \frac{8 - 1}{-3 - 6} \][/tex]
[tex]\[ \text{slope} = \frac{7}{-9} \][/tex]
[tex]\[ \text{slope} = -\frac{7}{9} \][/tex]

Therefore, the correct answer is:
B. [tex]\(-\frac{7}{9}\)[/tex]
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