Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Answer:
2.$25 off one purchase of 75$ or more
Step-by-step explanation:
Percentages
When a percentage, say n%, is deducted from a value, it means that the original value is being subtracted by the product of the decimal form of the percent and the value itself or,
[tex]V-(\dfrac{n}{100} )V[/tex].
To find the percentage of any value, the value must be multiplied by the percent's decimal equivalent.
Another way that the new value can be calculated is by taking the product of the original value and the decimal form of (100-n)% or " decimal form of the remaining percent".
Simplifying the expression made earlier proves this,
[tex]V-(\dfrac{n}{100} )V=(\dfrac{100}{100} )V-(\dfrac{n}{100} )V\\\\\Longrightarrow (\dfrac{100-n}{100} )V[/tex].
Apply Percentages to the Problem
If 25% is taken off of a price of $88, then the new value is,
[tex](\dfrac{100-25}{100} )(88)=(\dfrac{75}{100} )(88)=0.75(88)=66[/tex].
---------------------------------------------------------------------------------------------------------
Let's compare the new value to the other scenario where $25 dollars is deducted from any price over $75.
Since $88 > $ 75, $25 can be deducted, so the new value is 88 - 25 or, $63.
Since the second coupon gave Cassie a cheaper price of $63 compared to the $66 from earlier, it deducted more money, thus answer choice 2 is the correct answer.
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.