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You are making a salt water solution. If you use 2.8 moles of NaCl and make a 2.2 Liter solution, what molarity would it be? Your
answer should go to two decimal places.

Sagot :

GinnyAnswer
Certainly! Let's find the molarity of the salt water solution step-by-step.

Step 1: Understand the Variables
- Moles of NaCl (solute): 2.8 moles
- Volume of the solution (solvent): 2.2 liters

Step 2: Recall the Formula for Molarity
Molarity (M) is defined as the number of moles of solute per liter of solution. The formula is:

[tex]\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} \][/tex]

Step 3: Substitute the Given Values into the Formula
Using the values provided:
- Moles of NaCl: 2.8 moles
- Volume of the solution: 2.2 liters

[tex]\[ \text{Molarity} = \frac{2.8 \text{ moles}}{2.2 \text{ liters}} \][/tex]

Step 4: Perform the Division
Calculate the molarity by dividing 2.8 moles by 2.2 liters:

[tex]\[ \text{Molarity} = \frac{2.8}{2.2} \approx 1.272727 \][/tex]

Step 5: Round the Result to Two Decimal Places
Rounding the result to two decimal places:

[tex]\[ \text{Molarity} \approx 1.27 \][/tex]

Final Answer
The molarity of the salt water solution is [tex]\( \boxed{1.27} \text{ M} \)[/tex].
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