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A race car completes the final lap of a race on a 2-kilometer circular track. At the start of the lap, it crosses the line at 60 meters/second. It completes the lap 28.57 seconds later, crossing the line at 85 meters/second. Calculate the displacement and average acceleration of the car along the track over the course of the final lap.
A. Displacement is 0 meters, and acceleration is 0.88 meters/second2.
B. Displacement is 2,000 meters, and acceleration is 1.14 meters/second2.
C. Displacement is 0 meters, and acceleration is 70.0 meters/second2.
D. Displacement is 2,000 meters, and acceleration is 80.0 meters/second2.
E. Displacement is 0 meters, and acceleration is 0.70 meters/second2.

Sagot :

MathPhys

Answer:

A. Displacement is 0 meters, and acceleration is 0.88 meters/second2

Explanation:

Displacement is the change in position. In other words, it is the distance between the car's starting point and ending point. Acceleration (a) is the change in velocity (Δv) over time (Δt), where velocity is the speed and direction of the car.

Since the car travels in a circle and returns to the same point it started from, its displacement is 0 meters.

The acceleration is:

a = Δv / Δt

a = (85 m/s − 60 m/s) / (28.57 s)

a = 0.88 m/s²

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