Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Answer:
There is no certified answer for this question so we are just ging to tell you how to do it based on our understanding.
Step-by-step explanation:
Certainly! Let’s break this down step by step.
Equation for the Value of the Machine: The value of the machine is given by the equation: [ v = (-0.45)t^{5.8} ]
Graphing the Equation: To graph this equation, we’ll plot points using different values of (t) and corresponding values of (v). Let’s choose a few values of (t):
When (t = 0), the value of the machine is: [ v(0) = (-0.45)(0)^{5.8} = 0 ]
When (t = 1), the value of the machine is: [ v(1) = (-0.45)(1)^{5.8} ]
When (t = 2), the value of the machine is: [ v(2) = (-0.45)(2)^{5.8} ]
And so on for other values of (t).
Estimating the Value After 1 Year: Let’s calculate the value of the machine after 1 year: [ v(1) = (-0.45)(1)^{5.8} ] Using a calculator or software, we find that (v(1) \approx -0.45). Therefore, the estimated value of the machine after 1 year is approximately $450 (in thousands of dollars).
Graph: Here’s a rough sketch of the graph of the equation (v = (-0.45)t^{5.8}): !Graph of v = (-0.45)t^{5.8} Note that the graph is decreasing because of the negative coefficient (-0.45).
Remember that this is an estimate based on the given equation. Actual market fluctuations and other factors may affect the machine’s value.
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.