Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Step-by-step explanation:
To find the depth of the water in the cylindrical container, we need to use the concept of similar triangles.
The ratio of the corresponding dimensions of two similar figures is the same.
Here, the ratio of the radius of the cone to the cylindrical container is \( \frac{28}{20} \), and the ratio of the height of the cone to the height of the cylindrical container is \( \frac{30}{h} \), where \( h \) is the depth of water in the cylindrical container.
So, we can set up the proportion:
\( \frac{28}{20} = \frac{30}{h} \)
Cross-multiplying, we get:
\( 28 \times h = 20 \times 30 \)
\( 28h = 600 \)
\( h = \frac{600}{28} \)
\( h ≈ 21.43 \) cm
So, the depth of the water in the cylindrical container is approximately 21.43 cm.
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
