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What is, 7 3/10+6 1/3+2 7/10?

Sagot :

mel2169

7 3/10 + 6 1/3 + 2 7/10

First change them to improper fractions

73/10 + 19/3 + 27/10

now find the common denominator which would be 30

73/10 = 219 /30

19/3 =   190/30

27/10 =  81 /30

now add (219 + 190 + 81) = 490/30

now divide 490 ÷ 30 = 16 1/3

Your answer is 16 1/3

Hope this helps. :)
We are going to add 7 3/10 and 2 7/10 first. [tex]\boxed{\boxed{7 \frac{3}{10}}}+\boxed{\boxed{2 \frac{7}{10}}}}=\boxed{\boxed{9 \frac{10}{10}}}[/tex]. Now we are going to add [tex]\boxed{\boxed{9{ \frac{10}{10}}}}[/tex] by [tex]\boxed{\boxed{6{ \frac{1}{3}}}}[/tex]. [tex]\boxed{\boxed{9{ \frac{10*3}{10*3}}}}=\boxed{\boxed{9{ \frac{30}{30}}}} \ and \ \boxed{\boxed{6 \frac{1*10}{3*10}}}}=\boxed{\boxed{6{ \frac{10}{30}}}}[/tex]. Finnally we add.[tex]\boxed{\boxed{9{ \frac{30}{30}}}}+{\boxed{\boxed{6{ \frac{10}{30}}}}=\boxed{\boxed{15 \frac{40}{30}}}}.[/tex]. Last, but not least we simplify,[tex]\boxed{\boxed{15{ \frac{30:10}{40:10}}}}=\boxed{\boxed{15 \frac{3}{4}}}}[/tex]. Therefore, your answer is [tex]\boxed{\boxed{15 \frac{3}{4}}}}[/tex]. Hoped I helped. :)
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