Ajohnson2199
Answered

Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

The probability that a train leaves on time is 0.9. The probability that the train arrives on time and leaves on time is 0.36. What is the probability that the train arrives on time, given that it leaves on time?

0.4
0.9
0.27
0.36

Sagot :

P(arrives on time given leaves on time)=
P(B | A)= P(B n A) / P(A)
= P(A n B) / P(A)
= 0.36 / 0.9
= 0.4
MrRoyal

The probability that the train arrives on time, given that it leaves on time is 0.4

How to determine the probability?

The given parameters are:

  • P(Leave on time) = 0.9
  • P(Arrive and Leave on time) = 0.36

The required probability is calculated using:

P(Arrive on time given that it leaves on time) = P(Arrive and Leave on time)/P(Leave on time)

So, we have:

P(Arrive on time given that it leaves on time) = 0.36/0.9

Evaluate

P(Arrive on time given that it leaves on time) = 0.4

Hence, the probability that the train arrives on time, given that it leaves on time is 0.4

Read more about probability at:

https://brainly.com/question/25870256

#SPJ1

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.