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Sagot :
part a :
Area = π*r² = π(d/2)² = π*(8/2)² =
π*4² = π*16 square inches
Part b
d=8+4 = 12 and r = d/2 = 6inches
We know :
Area = π*r²
Area = π*6²
=36π
Area = π*r² = π(d/2)² = π*(8/2)² =
π*4² = π*16 square inches
Part b
d=8+4 = 12 and r = d/2 = 6inches
We know :
Area = π*r²
Area = π*6²
=36π
Break it down.
Hint : Radius is half the diameter, 8 / 2 = 4
Part A:
A = πr^2
A = π(4)^2
A = π16
Part B :
C = πd
C = π8
but its 2in. wide
C = π8 x 2
C = π16
From the previous question, I know the area is π16
A = π16 + C = π16 = π32
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