Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Find the slope of the line containing the pair of points.
(-10,-3) and (-12,-10)
the slope of the line is...........???

Sagot :

iGreen
[tex]\sf~m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

(-10, -3), (-12, -10)
  x1  y1    x2   y2

Plug in what we know:

[tex]\sf~m=\dfrac{-10-(-3)}{-12-(-10)}[/tex]

Subtract:

[tex]\sf~m=\dfrac{-7}{-2}[/tex]

Divide:

[tex]\sf~m=\boxed{\sf3.5}[/tex]
Panoyin
[tex]m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-10 - (-3)}{-12 - (-10)} = \frac{-10 + 3}{-12 + 10} = \frac{-7}{-2} = 3\frac{1}{2}[/tex]

The slope of the line is equal to 3¹/₂.

[tex]y - y_1 = m(x - x_1) \\y - (-3) = 3\frac{1}{2}(x - (-10) \\y + 3 = 3\frac{1}{2}(x + 10) \\y + 3 = 3\frac{1}{2}(x) + 3\frac{1}{2}(10) \\y + 3 = 3\frac{1}{2}x + 35 \\y = 3\frac{1}{2}x + 32[/tex]
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.