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Sagot :
So, since there are two equations, we can substitute one of them into the other. In this case, it would be easiest to substitute 2b=6a-14 into the other equations. But first, simplify by dividing both sides by 2. You bet b=3a-1
We can now plug this into the other equation
Sine the equation b=3a-1 results in the value of b, we have to plug in for the value of b in the other equation
So this is what we get after plugging in:
3a-(3a-1)=7
Now, simplify. 3a-3a+1=7
Since 3a-3a = 0, this equation results in a no solution
Answer:
The result is a no-solution, or Ф
Hope this helped!! :D
We can now plug this into the other equation
Sine the equation b=3a-1 results in the value of b, we have to plug in for the value of b in the other equation
So this is what we get after plugging in:
3a-(3a-1)=7
Now, simplify. 3a-3a+1=7
Since 3a-3a = 0, this equation results in a no solution
Answer:
The result is a no-solution, or Ф
Hope this helped!! :D
2b=6a-14
3a-b=7
(rearrange so that all the a's b's and numbers line up) *better if number alone
2b - 6a = -14
-b + 3a = 7
(never have a negative number in the front so change whole equation)
2b - 6a = -14
b - 3a = -7
now try to get ride of some numbers.....get rid of the negative 6 and 3 by finding a way to make the numbers the same
2b - 6a = -14
2b - 6a = -14 ......multiply each number by two and you get the same equation as above
It is impossible to find a or be because the equations are the same just one in a reduce form
3a-b=7
(rearrange so that all the a's b's and numbers line up) *better if number alone
2b - 6a = -14
-b + 3a = 7
(never have a negative number in the front so change whole equation)
2b - 6a = -14
b - 3a = -7
now try to get ride of some numbers.....get rid of the negative 6 and 3 by finding a way to make the numbers the same
2b - 6a = -14
2b - 6a = -14 ......multiply each number by two and you get the same equation as above
It is impossible to find a or be because the equations are the same just one in a reduce form
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