Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

2log4-log3+2logx-4=0

Sagot :

2log4-log3+2logx-4=0
I assume it's find x
2log4=log4^2=log16
2logx=logx^2
-log3=log3^(-1)=log1/3
log(16x^2)/3=4
base is unknown, so if it's different just plug it in for the lower values of 10
we'll just assume it's common log's base is 10
10^4=(16x^2)/3
30000=16x^2
x^2=30000/16
x=(30000^1/2)/4 which is about 43.301