Picknell14
Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Ask your questions and receive precise answers from experienced professionals across different disciplines. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

What is the derivative of y=ln(sec(x)+tan(x))y=ln(sec(x)+tan(x))?

Sagot :

kittymaniac
The derivative of ln(u) is 1/u * the derivative of u.

[tex]y = ln(sec(x)+tan(x)) \\ \\ y' = \frac{1}{sec(x)+tan(x)} * [tan(x)sec(x) + sec^2(x)] \\ \\ y' = \frac{sec(x)(sec(x) + tan(x))}{sec(x)+tan(x)} \\ \\ y' = sec(x) + C[/tex]

I hope this helps! :)
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.