Answered

Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

When a family with 2 adults and 3 children bought tickets for an amusement park, they paid a total of $56.50. The next family, with 4 children and one adult, paid $49.50. What was the price of an adult ticket and a child ticket using system of equations.

Sagot :

a=adult
c=child
Equation 1 (the first family)
2a+3c=56.5
Equation 2 (the second family)
a+4c=49.5 multiply by 2
2a+8c=99  multiply by -1
-2a-8c=-99
Systems of Equations
    (2a+3c=56.5)
+  (-2a-8c=-99)
-------------
         -5c=-42.5
             c=$8.5
Substitute
2a+3*8.5=56.5
2a+25.5=56.5
2a=31
a=$15.5
Conclusion
Adult Ticket: $15.5
Child Ticket: $8.5


logo88
The cost of an adult ticket is $15.50 and the cost of a child ticket is $8.50
Proof:
Set up a system of equations calling Adults a and Children c
2a+3c= $56.50 (equation 1)
4c+a= $49.50 (equation 2)
a= -4c+49.50 (i subtracted 4c to both sides) (label equation 3)
sub equation 3 into equation 1
2(-4c+49.50)+3c= 56.50
-8c+99+3c=56.50
-5c+99=56.50
     -99    -99
-5c = -42.50
c= -42.50/ -5
c= 8.50
sub c=8.50 into equation 3 to find adult price
a= -4(8.5)+49.50
a= 15.50

Therefore Child Cost = $8.50 and Adult Cost= $15.50

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.